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2 years ago

The duckbill platypus and spiny anteater are the only two known

Physics

1 answer:

Iteru [2.4K]2 years ago

3 0

Answer:

I believe it is False.

Explanation:

Hope my answer has helped you!

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A 762 kg car experiences a braking force of 9045 N and skids to a stop in 4.3 seconds. What is the speed of the car just before

PilotLPTM [1.2K]

Answer:

The solution for this problem is:

We will be using the formula for force which is F = ma

=>10,000 = 2000 * a

but we need to solve for acceleration so divide both sides by 2000, we will get:

=>a = 5 m/s^2

Let the initial velocity was u m/s

=>By v = u - at

=>0 = u - 5 x 6

Since acceleration is constant the velocity can be computed by multiplying the acceleration by 6 seconds.

=>u = 30 m/s

Explanation:

6 0

2 years ago

In a crash test, a 1000 kg automobile moving at 10 m/s crashes into a brick wall. How much energy goes into demolishing and warm

marishachu [46]

Answer:

Explanation:

Given

mass of automobile $m=1000\ kg$

velocity of automobile $v=10\ m/s$

If the automobile crashes into the brick wall then it's kinetic energy is converted into thermal and demolishing energy to wall.

Car completely stops as it crashes into the wall so Energy converted into demolition and thermal energy

$E=\frac{1}{2}mv^2$

$E=\frac{1}{2}\times 1000\times (10)^2$

$E=50\ kJ$

8 0

2 years ago

An explanation for planetary differentiation is_____________.

Luda [366]

Answer:

C. The process through which distinct layers with characteristic chemical and/or physical properties are formed

Explanation:

I know It cause i took that test last year. Just wanna help GL.

5 0

2 years ago

The position of a 2.2 kg mass is given by x=(2t3â5t2) m, where t is in seconds.

Juliette [100K]

B b b b b b b bb bb bb b b b b b b b b b

6 0

3 years ago

Peg P is driven by the forked link OA along the path described by r = eu, where r is in meters. When u = p4 rad, the link has an

8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 $m/s^2$ where as radial the component of acceleration is 8.77 $m/s^2$

Explanation:

As per the given data

u=π/4 rad

ω=u'=2 rad/s

α=u''=4 rad/s

$r=e^u$

So the transverse component of acceleration are given as

$a_{\theta}=(ru''+2r'u')\\$

Here

$r=e^u\\r=e^{\pi/4}\\r=2.1932 m$

$r'=e^u.u'\\r'=2.1932 \times 2\\r'=4.3864 m$

$a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\$

The transverse component of acceleration is 26.32 $m/s^2$

The radial component is given as

$a_r=r''-r\theta'^2$

Here

$r''=e^u.u'^2+e^u u''\\r''=2.1932 \times (2)^2+2.1932\times 4\\r''=17.5456 m$

$a_r=r''-ru'^2\\a_r=17.5456-2.1932\times (2)^2\\a_r=8.7728 m/s^2$

The radial component of acceleration is 8.77 $m/s^2$

6 0

3 years ago