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Troyanec [42]
3 years ago
10

Which of the following is a list of

Physics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

c. metallic, sub metallic, or nonmetallic

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CaHeK987 [17]

Answer:

true?

Explanation:

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3 years ago
Describe how the doppler effect explains why a siren has a lower pitch as a fire engine moves away from you. How does the freque
Elena L [17]
The Doppler effect is the change in sound or light that occurs whenever there is motion between the source and its observer. The siren of the fire engine has a lower pitch as it moves away because the waves are now spread out causing a lower frequency and a lower pitch. High-frequency sound waves have a higher pitch and higher energy than low-frequency waves. 
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In a elastic lab what did you change and why?
Vilka [71]

I changed my undershorts.  The elastic on the old ones I put on that day was deteriorated, and it completely failed when I dripped lab coffee on it, causing falldown.

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A new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radi
Mariulka [41]

Answer:

Mass of star is 1.31\times10^{35} kg.

Explanation:

The cube of orbital radius is equal to the square of its orbital time period is known as Kepler's law.

T^{2} = (\frac{4\pi^{2} }{GM})r^{3}          .....(1)

Here T is time period, r is orbital radius, G is universal gravitational constant and M is the mass of the star.

According to the problem,

Time period, T = 109 days = 109 x 24 x 60 x 60 s = 9.41 x 10⁶ s

Orbital radius, r = 18 AU = 18 x 1.496 x 10¹¹ m = 2.70 x 10¹² m

Gravitational constant, G = 6.67 x 10⁻¹¹ m³ kg⁻¹ s⁻²

Substitute these values in equation (1).

(9.41\times10^{6}) ^{2} = (\frac{4\pi^{2} }{6.67\times10^{-11}\times M})(2.70\times10^{12}) ^{3}

M = 1.31\times10^{35} kg

3 0
3 years ago
A linear elastic spring can be compressed 10. 0 cm by an applied force of 5. 0 N. A 4. 5
Daniel [21]

The maximum compression of the spring is 0.6 m.

<h3>Spring constant</h3>

The spring constant of the spring is calculated as follows;

F = kx

k = F/x

k = (5)/(0.1)

k = 50 N/m

<h3>Maximum compression of the spring</h3>

The maximum compression of the spring is calculated as follows;

U = K.E

¹/₂kx²  = ¹/₂mv²

x² = (mv²)/(k)

x = √(mv²)/(k)

x = √(4.5 x 2²)/(50)

x = 0.6 m

Thus, the maximum compression of the spring is 0.6 m.

Learn more about spring constant here: brainly.com/question/1968517

4 0
2 years ago
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