Answer:
96.21 ft/s
Explanation:
To solve this, you only need to use one expression which is:
Vf² = Vo² + 2gh
g = 9.8 m/s²
However, this exercise is talking in feet, so convert the gravity to feet first:
g = 9.8 * 3.28 = 32.15 ft/s²
Vo is zero, because it's a free fall and in free fall the innitial speed is always zero. With this, let's calculate the speed at 2 seconds, with a height of 64 ft, and then with the 256 ft:
V1 = √2*32.15*64
V1 = 64.15 ft/s
V2 = √2*32.15*256
V2 = 128.3 ft/s
So the average rate is:
V = 128.3 + 64.15 / 2
V = 96.22 ft/s
All the spheres interact with other spheres. For example, rain (hydrosphere) falls from clouds in the atmosphere to the lithosphere and forms streams and rivers that provide drinking water for wildlife and humans as well as water for plant growth (biosphere). ... Flooding rivers wash away soil.
Answer:
V' = V/2
Explanation:
The voltage across a parallel plate capacitor is given as follows:
V = Q/C
where,
V = Voltage across capacitor
Q = Charge on Capacitor
C = Capacitance of Capacitor = A∈₀/d
Therefore,
V = Qd/A∈₀
where,
A = Area of plate
d = distance between plates
∈₀ = permittivity of free space
FOR CAPACITOR 1:
Q = Q
d = d
A = A
V = V
Therefore,
V = Qd/A∈₀ --------------- equation (1)
FOR CAPACITOR 2:
V' = ?
Q' = Q
d' = d
A' = 2A
Therefore,
V' = Q'd'/A'∈₀
V' = Qd/2A∈₀
V' = (1/2)(Qd/A∈₀)
using equation (1):
<u>V' = V/2</u>
Answer:
A) C = 4.425 10⁻¹³ F, B) Q = 6.31 10⁻¹¹ C, C) E = 8.9 10⁴ N / C,
D) u_{E} = 3.19 10⁻⁹ J
Explanation:
Part A. Capacitance is
C = ε₀ A / d
in this case distance is d = 0.800 cm = 0.800 10⁻² m and the area of the plates is x = 0.200 cm= 0.2 10⁻² m, all the quantities must be in the SI system for the result to be in Farads
A = x²
A = (0.2 10⁻²)²
A = 4 10⁻⁶ m
let's calculate
C = 8.85 10⁻¹² 4 10⁻⁶ / 0.8 10⁻²
C = 44.25 10⁻¹⁴ F
C = 4.425 10⁻¹³ F
Part B. The charge on each plate is
Q = C ΔV
Q = 4.425 10⁻¹³ 120
Q = 6.31 10⁻¹¹ C
Part C. the electric field of a plate is
E = σ / 2ε₀
where the charge density is
σ = Q / A
we substitute
E =
let's calculate
E = 
E = 8.9 10⁴ N / C
Part D. stored energy
= ½ C V²
u_{E} = ½ 4.425 10⁻¹³ 120²
u_{E} = 3.19 10⁻⁹ J
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