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3 years ago

A lever in which the load is between the fulcrum and the applied force is a ________.

1 answer:

4 0

Hello there.

<span>A lever in which the load is between the fulcrum and the applied force is a ________.

Answer: It is a second class lever.

Hope This Helps You!
Good Luck Studying ^-^</span>

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Question 10 of 15<br> If the period of a wave increases, its frequency must blank

aniked [119]

Answer:

Blank = Increase

4 0

2 years ago

Three multiple choice science questions.

Ratling [72]

C
A
B
I HOPE THIS HELPS

6 0

3 years ago

Suppose the U.S. national debt is about $14 trillion. If payments were made at the rate of $3,500 per second, how many years wou

andreyandreev [35.5K]

Answer:

It will take 126.84 years to pay off the debt

Explanation:

Total debt = $14,000,000,000,000.00

Paid $3,500 per second

Number of seconds to pay off the debt will be:

14 ×10^12 /3500

Number of seconds = 4× 10^9 seconds

Converting seconds to year:

I second = 3.171 ×10^-8 calendar year

Therefore, number of years it will take to pay off $14 Trillion =( 4 ×10^9 ) × ( 3.171 × 10^-8)

Number of years = 126.84 years

5 0

3 years ago

The largest watermelon ever grown had a mass of 118 kg. Suppose this watermelon were exhibited on a platform 5.00 m above the gr

WINSTONCH [101]

Answer: height = 3.98m

Explanation: by placing the watermelon at a height above the ground, it has a potential energy of the formulae

p = mgh

p = potential energy = 4.61kJ = 4610J

m = mass of watermelon = 118 kg

g = acceleration due gravity = 9.8 m/s²

4610 = 118 * 9.8 * h

h = 4610/ 118 * 9.8

h = 4610/ 1156.4

h = 3.98m

6 0

3 years ago

While on a playground, you and your niece take turns sliding down a frictionless slide. Your mass is 75 kg while your little nie

Olenka [21]

Answer:

Explanation:

In absence of friction, total mechanical energy must be conserved.
This means that the change in gravitational potential energy (in magnitude) must be equal to the change in kinetic energy:

$\Delta K = \Delta U \\ \\ \frac{1}{2} * m* v^{2} = m*g*h$

As it can be seen, the mass m is on the both sides of the equation, which means that it can be simplified.
We can solve this equation for v (speed at the bottom) as follows:

$v = \sqrt{2*g*h}$

As it can be seen, the mass has no part in the equation, so, due both are starting from the same height, both people have the same speed at the bottom.
The option c is the right one.

6 0

2 years ago