Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
(4x - 3)(3x² + 1)
Step-by-step explanation:
Given
12x³ - 9x² + 4x - 3 ( factor the first/second and third/fourth terms )
= 3x²(4x - 3) + 1(4x - 3) ← factor out (4x - 3) from each term
= (4x - 3)(3x² + 1) ← in factored form
Answer:
Step-by-step explanation:
Answer:
<h2>27ft³</h2>
Step-by-step explanation:
1 yard = 3 feet
therefore 3 yards = 3(3 feet) = 9 feet
3yd × 3ft × 1ft = 9ft × 3ft × 1ft = 27ft³
