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motikmotik
4 years ago
11

Solve the equation. $x^2=100$

Mathematics
1 answer:
Xelga [282]4 years ago
3 0
$ = 10

10^2 = 100

Hope that helps
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Pls! What function is it??
SOVA2 [1]

Answer:

the second one is the anwser

Step-by-step explanation:

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3 years ago
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HELP I NEED IT RN
SVETLANKA909090 [29]

Answer: (How much does your dog weigh?)

Step-by-step explanation: A statistical question is a question that has more than one possible answer. The only question that has more than one possible answer is "How much does your dog weigh?"

Statistical questions are more than one answer with numbers.

8 0
3 years ago
Please explain it and tell me how u got the answer<br> Thx
denis-greek [22]
The y-intercept of a function is that function's value when x=0.
.. f(0) = 4
.. g(0) = 0
These y-intercepts differ by 4.

If you want them to differ by zero (be the same), you have to move them to the same point.

Selection 1. Moves f(0) down 3 (to 1) and g(0) up 1 (to 1), so moves the y-intercepts to the same point. This is what you want, so this is an appropriate answer selection.

Selection 2. Moves f(0) up 4 (to 8) and g(0) down 1 (to -1). 8 and -1 are not the same point, so this is not the answer.

Selection 3. Moves f(0) down 2 (to 2) and g(0) up 1 (to 1). 2 and 1 are not the same point, so this is not the answer.

Selection 4. Moves f(0) up 3 (to 7) and g(0) down 6 (to -6). 7 and -6 are not the same point, so this is not the answer.

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The appropriate choice is the 1st one.
&nbsp; f(x) - 3 and
&nbsp; g(x) + 1

4 0
4 years ago
50x^5<br>÷ <br>10x^3<br><br>need done asap​
Lina20 [59]

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5 0
4 years ago
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Find the absolute extreme of the function on the closed interval. y=9e^xsinx , [0,pi]
Molodets [167]

For convenience sake, I will let y=f(x)=9e^{x}\sin x

First, we evaluate the function at the endpoints of the interval.

f(0)=9e^{0}\sin(0)=0\\\\f(\pi)=9e^{\pi}\sin(\pi)=0

Then, we need to find the critical points.

We can start by taking the derivative using the power rule.

f'(x)=9e^{x} \frac{d}{dx} \sin x+9\sin x \frac{d}{dx} e^{x}=9e^{x}(\cos x+\sin x)

Setting this equal to 0,

9e^x (\cos x+\sin x)=0

Since 9e^x > 0, we can divide both sides by 9e^x.

\cos x+\sin x=0\\\\\sin x=-\cos x\\\\\tan x=-1\\\\x=\frac{3\pi}{4}

f\left(\frac{3\pi}{4} \right)=9e^{3\pi/4}\sin \left(\frac{3\pi}{4} \right)=\frac{9\sqrt{2}e^{3\pi/4}}{2}

So, the absolute minimum is \boxed{\left(\frac{3\pi}{4}, \frac{9\sqrt{2}e^{3\pi/4}}{\sqrt{2}} \right)} and the absolute minima are \boxed{(0,0), (\pi, 0)}

3 0
2 years ago
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