Answer:
area-34
permiter-68
Step-by-step explanation:
Using the normal distribution, the z-score that separates the bottom 70% from the top 30% is z = 0.525.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The z-score that separates the bottom 70% from the top 30% is <u>z with a p-value of 0.7</u>, hence z = 0.525.
More can be learned about the normal distribution at brainly.com/question/24537145
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Answer:
Total number of ways 6 red marbles can be chosen=541549008
Step-by-step explanation:
16 marbles are chosen in which 6 are red marbles and remaining marbles ,which are 10, are blue marbles.
In order to find in how many ways 6 red marbles can be chosen we will proceed as:
Out of 17 red marbles 6 are chosen and out of 18 blue marbles 10 are chosen.
Total number of ways 6 red marbles can be chosen= ![17_{C_6} * 18_{C_1_0}](https://tex.z-dn.net/?f=17_%7BC_6%7D%20%2A%2018_%7BC_1_0%7D)
Total number of ways 6 red marbles can be chosen=![\frac{17!}{6!*(17-6)!} * \frac{18!}{10!*(18-10)!}](https://tex.z-dn.net/?f=%5Cfrac%7B17%21%7D%7B6%21%2A%2817-6%29%21%7D%20%2A%20%5Cfrac%7B18%21%7D%7B10%21%2A%2818-10%29%21%7D)
Total number of ways 6 red marbles can be chosen= 12376*43758
Total number of ways 6 red marbles can be chosen=541549008