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timurjin [86]
4 years ago
12

Round 3.99998 to 4 decimal places (answer is not 4.0000)

Mathematics
1 answer:
Brums [2.3K]4 years ago
4 0
I need help on this too
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evelyn drinks 8 glasses of water a day,which is56 glasses a week. How many glasses of water does she drink
vlada-n [284]
1 year=52 weeks

So just multiply it by 56

52*56= 2912 glasses per year
6 0
4 years ago
Writing Probability as a Fraction
katrin [286]
Probability=(number of specific outcomes)/(number of possible outcomes)

There are 4+2+6+5=17 total marbles so:

P(Yellow)=4/17

P(Blue)=2/17

P(Black)=5/17

P(Red)=6/17
8 0
4 years ago
Read 2 more answers
How are √25 and √-25 different in the terms of a solution for both? *
Tanya [424]

Answer:

For \sqrt{25} it will be plus or minus \sqrt{5}

For \sqrt{-25} it will be plus or minus \sqrt{5i}

Step-by-step explanation:

Well for \sqrt{-25} it will be 5i

Because i = -1  

6 0
3 years ago
List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers,
Anarel [89]

Answer: YES

Step-by-step explanation:

We need to write out the expressions

P= {m}

Q= {n}

R= {m+n}

If 2m=n then we can say;

P= {½n} Q= {n} & R= {³/²n}

It is obvious that the smaller number in Q is greater than the largest number in P

We can make some assumptions.

Let n= (x,y,z)

Consequently,

P={½x,½y,½z} Q={x,y,z} and R= {1.5x,1.5y,1.5z}

Therefore the median will be the middle element,

Median of P= ½y

Median of Q = y

Median of R = 1.5y

And 1.5y>1.5y

Then we can agree that the median of R is greater than the median of both P and Q

5 0
4 years ago
Which of the following expressions is a factor of the polynomial x 2 +3/2x-1
Elodia [21]

Answer:

\large \boxed{\sf \ \ \ (x+2)(x-\dfrac{1}{2}) \ \ \ }

Step-by-step explanation:

Hello,

let's solve

x^2+\dfrac{3}{2}x-1=0\\\\ 2x^2+3x-2=0 \ \text{multiply by 2}\\\\\\

\Delta=b^2-4ac=9+4*2*2=9+16=25

There are two solutions

x_1=\dfrac{-3-\sqrt{25}}{4}\\\\x_1=\dfrac{-3-5}{4}\\\\x_1=\dfrac{-8}{4}\\\\\boxed{x_1=-2}

And

x_2=\dfrac{-3+\sqrt{25}}{4}\\\\x_2=\dfrac{-3+5}{4}\\\\x_2=\dfrac{2}{4}\\\\\boxed{x_2=\dfrac{1}{2}}

So we can write

x^2+\dfrac{3}{2}x-1\\\\=(x-x_1)(x-x_2)\\\\=(x+2)(x-\dfrac{1}{2})

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
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