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3 years ago

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Assume the sales representative calls 6 customers, and each call has 4 possible results: reaches the customer in person, gets an

answering machine, there is no answer, and gets a busy signal. A phone record is a list of the results of each call.
How many different phone records are possible?

1 answer:

KonstantinChe [14]3 years ago

8 0

Answer:

81

Step-by-step explanation:

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What is the point-slope form given the following slope and a point on the line? m = 3/7 , (7, -4)

GarryVolchara [31]

Answer:

The equation is y = (3/7)x - 7.

Step-by-step explanation:

Given that the point slope form of an equation is y = mx + b where m represents the gradient and b is the y-intercept. Then, you have to substitute the following values into the equation :

$y = mx + b$

$let \: m = \frac{3}{7} ,x = 7,y = - 4$

$- 4 = \frac{3}{7} (7) + b$

$- 4 = 3 + b$

$- 4 - 3 = b$

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3 years ago

WILL MARK BRIANLIEST!

gayaneshka [121]

Answer:

(4, - 2 )

Step-by-step explanation:

Given the 2 equations

x + y = 2 → (1)

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Substituting in (1)

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3 years ago

3. 325 Students attend a school, 195 are girls <br> Give the proportion of boys as a decimal

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3 years ago

One thousand independent rolls of a fair die will be made. Compute an approximation to the probability that the number 6 will ap

pashok25 [27]

Answer:

0.19

Step-by-step explanation:

We are given that

Number of rolls of die=n=1000

Let the event of six coming up be success.Then, in each trial , the probability of success =p=P(success)=P(6)= $\frac{1}{6}$

Let X be the random variable for the number of sixes in the 1000 rolls of die.

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Since, n is very large,the binomial random variable can be approximated as normal random variable.

Mean, $\mu=np=1000\times \frac{1}{6}=166.67$

Variance= $\sigma^2=np(1-p)=1000\times \farc{1}{6}\times (1-\frac{1}{6})=1000\times \frac{5}{36}=138.89$

$X\sim N(166.67,138.89)$

$P(150\leq X\leq 200)=P[\frac{150-166.67}{11.79}\leq \frac{X-\mu}{\sigma}\leq \frac{200-166.67}{11.79}]$

= $P[-1.41\leq Z\leq 2.83]=P[Z\leq 2.83]-P[Z$

= $\phi(2.83)-\phi(-1.41)$

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Now, given that 6 appears exactly 200 times .

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Therefore, for 800 rolls, let the event of 5 coming up be success.

Then , p=P(success)=P(5)= $\frac{1}{5}$

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Then, $Y\sim bin(800,\frac{1}{5})$

Mean, $\mu=np=800\times \frac{1}{5}=160$

Variance, $\sigma^2=np(1-p)=800\times \frac{1}{5}(1-\frac{1}{5})=128$

$Y\sim N(160,128)$ because n is large

$P(Y$

$P(Y$

Hence, the probability that the number 5 will appear less than 150 times given that 6 appeared exactly 200 times=0.19

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2 years ago

A new pair of tennis shoes at shoe show costs $80. They are on sale for 1/4 off. The sales tax is 5%. Find the total price.

oee [108]

80* 1/4= 20
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I hope this is correct, good luck!

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3 years ago