2 years ago

I need help so somebody plz help me

Mathematics

1 answer:

Anettt [7]2 years ago

5 0

Answer: A

This is simple. Absolute value inequalities can NOT have a negative. For D, the absolute value is not completely simplified. The negative sign will be removed in the process of solving it.

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Can you prove that DEF = HGF.!? Justify your answer.

frosja888 [35]

Step-by-step explanation:

$In \: \triangle DEF \: \& \: \triangle HGF \\ EF \: \cong \: GF...(given) \\ \angle EFD \cong \angle GFH \\ (vertically \: opposite \: angles) \\ \ DF \: \cong \: HF...(given) \\ \therefore \: \triangle DEF \cong \triangle HGF \\ (By\: SAS \:criterion\: of \:congruence)$