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3 years ago

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Find the distance between points A (10,-1) and B (-2,5). Round to the nearest tenth

1 answer:

bija089 [108]3 years ago

7 0

Answer:

<h2>The answer is 13.4 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A (10,-1) and B (-2,5)

The distance is

$|AB| = \sqrt{ ({10 + 2})^{2} + ({ - 1 - 5})^{2} } \\ = \sqrt{ {12}^{2} + ({ - 6})^{2} } \\ = \sqrt{144 + 36} \: \: \: \: \: \: \: \\ = \sqrt{180} \\ = 6 \sqrt{5} \: \: \\ =13.416407$

We have the final answer as

<h3>13.4 units to the nearest tenth</h3>

Hope this helps you

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Step-by-step explanation:

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See attachment for the formatted data

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$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

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