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3 years ago

How many 4-digit numbers are multiples of at least one of these two numbers: 2; 5.

Mathematics

1 answer:

hodyreva [135]3 years ago

8 0

Answer:

There are <u><em>5400</em></u> 4 digit numbers with these two numbers.

Step-by-step explanation:

To get this, you have to find the number of multiples of 2, which is 9000 4 digit numbers, which is 4500, and for 5, it would be 9000/5 = 1800.

So we have 4500 and 1800.

We first have to figure out the union of these two sets (the numbers listed in the two sets with no repeating numbers.

So to do this, we need to figure out how many 4 digit numbers for 10 because that is the repeat which is 2 times 5 = 10.

Now, we divide the 9000 4-digit numbers by 10 to get 900

Finally, we add the 4500, and 1800, and subtract the repeating part, which is 900

This makes the expression 4500+1800-900, which simplifies to 5400.

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What are some characteristics for simplest form

givi [52]

Ex. 9 divided by 3=3 because 3x3=9

7 0

3 years ago

Find four geometric means between 25 and 800.

SVEN [57.7K]

Actually, you have to find four missed terms of geometrical sequence. Denote

$a_1=25,\\ a_6=800$

and r - ratio, then

$a_2=a_1\cdot r=25r,\\a_3=a_1\cdot r^2=25r^2,\\a_4=a_1\cdot r^3=25r^3,\\a_5=a_1\cdot r^4=25r^4,\\a_6=a_1\cdot r^5=25r^5$ .

Since $a_6=800$ , you have that $800=25r^5$ , then

$r^5=\dfrac{800}{25} =32,\\r=2$ .

Now substitude r=2 in each of unknown 4 terms:

$a_2=25\cdot 2=50,\\a_3=25\cdot 2^2=100,\\a_4=25\cdot 2^3=200,\\a_5=25\cdot 2^4=400$ .

Answer: four geometric means between 25 and 800 are 50, 100, 200, 400.

8 0

4 years ago

Please help me answer this <3

ludmilkaskok [199]

Answer:

x = 30

Step-by-step explanation:

15 = 1/2x

multiply both sides of equation by 2

30 = x

3 0

3 years ago

What is the value of sin(t) if cos(t)=0.1, and t is in quadrant 1

Marizza181 [45]

Answer:

$sin(t)=\frac{\sqrt{99}}{10}$

Step-by-step explanation:

Remember that

If angle t belong to the First Quadrant

then

The value of sin(t) and cos(t) are positive values

we know that

$sin^2(t)+cos^2(t)=1$ ---> by trigonometric identity

we have

$cos(t)=0.1=\frac{1}{10}$

substitute

$sin^2(t)+(\frac{1}{10})^2=1$

$sin^2(t)+\frac{1}{100}=1$

$sin^2(t)=1-\frac{1}{100}$

$sin^2(t)=\frac{99}{100}$

$sin(t)=\frac{\sqrt{99}}{10}$

8 0

4 years ago

Pls help I keep asking and nobody’s helping me

patriot [66]

Answer: 268

Step-by-step explanation: substitute pi with 3.14, & then 4^3 as 64 in the second line. after, you multiply 3.14 x 64 you get 201 after you round. finally multiply 4 x 201 then divide your answer by 3. you get 268. (no one helped so i did)

8 0

3 years ago