Answer:

Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = 
=
= 
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.
Answer:
The answer is C one solution
Step-by-step explanation:
x-y=-14
-y=-x-14 bring x to the other side
y=x+14 divide everything by -1
-x-y=14
-y=x+14 bring x to the other side
y=-x-14 divide everything by -1
Answer:
Option A.
f(x) = -4*sin((1/3)*t + (π/6)) + 3
Step-by-step explanation:
We can easily solve this problem by using a graphing calculator or plotting tool.
The function is
f(t) = a*sin (b*t +c) + d
Please, see attached picture below.
By looking at the picture with all the possible cases, we can tell that the correct option is A.
The function has a period of T = 6π
Max . Amplitude = 7
Min . Amplitude = -1
Answer:
2x + y = 3.75
3x + 2y = 6
Step-by-step explanation:
x = cost of 1 hot dog
y = cost of 1 drink
Neveah: 2x + y = 3.75
Jason: 3x + 2y = 6
Answer:
the expected value of this raffle if you buy 1 ticket = -0.65
Step-by-step explanation:
Given that :
Five thousand tickets are sold at $1 each for a charity raffle
Tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $500, 3 prizes of $300, 5 prizes of $50, and 20 prizes of $5.
Thus; the amount and the corresponding probability can be computed as:
Amount Probability
$500 -$1 = $499 1/5000
$300 -$1 = $299 3/5000
$50 - $1 = $49 5/5000
$5 - $1 = $4 20/5000
-$1 1- 29/5000 = 4971/5000
The expected value of the raffle if 1 ticket is being bought is as follows:





Thus; the expected value of this raffle if you buy 1 ticket = -0.65