Answer: 172: 4= 43
43× 3= 129
172-129= 43
Odp.Wysłali 43 kupony do istniejących członków.
Step-by-step explanation:1.bo wysłali 3×wiecej i jeszcze są istniejący członkowie
2.ile wyslali potencialnym
3.i ile wyslali do istniejacych
The gcf of 15 and 10 is 5
Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.
With the first problem: You always divide from the left, then the rigth. 2+246/6 = 246/6=41 41+2=43
