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alekssr [168]
3 years ago
9

What is the basic notation for a proton?

Chemistry
1 answer:
Mama L [17]3 years ago
4 0

Answer:

p +  is the basic notation

You might be interested in
Name:_____________________________________________________ Date:___________ Period:_________ 3/23 - 3/27 Assignment 1: Gas Law P
crimeas [40]

Answer:

The answers are;

1. 8.2 liters

2. 1214.84 ml

3. 318.027 K

4. 4.00 l.

Explanation:

1. Boyle's law states that the volume of  given mass of gas is inversely proportional to its pressure at constant temperature

that is

P₁·V₁ = P₂·V₂

Where:

P₁ = Initial pressure = 40.0 mm Hg

V₁ = Initial volume = 12.3 liters

P₂ = Final pressure = 60.0 mm Hg

V₂ = Final volume = Required

From P₁·V₁ = P₂·V₂, V₂ is given by

V_2=\frac{P_1\cdot V_1}{P_2} = \frac{40.0 mm Hg\cdot 12.3 l}{60.0 mm Hg} =  8.2 l

The volume reduces to V₂ = 8.2 liters

2. Here Charles law states that

\frac{T_1}{V_1} =\frac{T_2}{V_2}

T₁ = Initial temperature = 27.0 °C = 300.15 K

V₁ = Initial volume = 900.0 mL

T₂ = Final temperature = 132.0 °C = 405.15 K

V₂ = Final volume = Required

Therefore  V_2 =\frac{T_2\cdot V_1}{T_1} = \frac{405.15 K\times 900.0 mL}{300.15 K} = 1214.84 ml

V₂ = 1214.84 ml

3.  Gay-Lussac's Law states that

\frac{T_1}{P_1} =\frac{T_2}{P_2}

Where:

P₁ = Initial pressure = 15.0 atmospheres

T₁ = Initial temperature = 25.0 °C = 298.15 K

P₂ = Final pressure = 16.0 atmospheres

T₂ = Final temperature = Required

∴ T_2 = \frac{T_1\times P_2}{P_1}

=  \frac{298.15 K\times 16.0atm}{15.0atm} = 318.027 K

T₂ = 318.027 K

4. Avogadro's law states that,

Equal volume of all gases at the same temperature and pressure contain equal number of molecules.

Therefore if 5.00 moles of gas occupies 2.00 l volume, then

1 moles will occupy 2.00/5 l volume and

10 moles will occupy 2.00/5 × 10 or 4.00 l volume.

6 0
4 years ago
29.0 argon combine completely with 4.30 g of Sulfur.
Iteru [2.4K]

Answer:

33.3

Explanation:

if we were to add 29.0 of argon and 4.30 of sulfur and that would come out 33.3.

8 0
3 years ago
2CO + O2  2CO2
murzikaleks [220]

Answer:

75 L Co2

37.5 L o2

Explanation:

welcome.

3 0
3 years ago
If the density of nitrogen gas at a certain pressure and temperature is 1.20 g/L, how many moles of nitrogen gas are in 15.0 L.
Irina18 [472]
<h3>Answer:</h3>

0.643 moles

<h3>Explanation:</h3>

We are given;

Density of nitrogen gas as 1.20 g/L

Volume nitrogen as 15.0 L

We are required to calculate the number moles of nitrogen gas;

<h3>Step 1: Determine the mass of nitrogen gas</h3>

We know the density is given by dividing mass by volume.

  • Density = Mass ÷ volume

Therefore, to get the mass;

  • Mass = Density × volume
  • Mass = 1.20 g/L × 15.0 L

        = 18 g

<h3>Step 2: Determine the mass of nitrogen gas </h3>

We know that to get the number of moles, we divide mass by molar mass;

That is, moles = Mass ÷ Molar mass

But, molar mass of nitrogen gas is 28 g/mol

Therefore;

Moles of nitrogen gas = 18 g ÷ 28 g/mol

                                     = 0.643 moles

Therefore, the number of moles of nitrogen gas 0.643 moles

5 0
4 years ago
Which will cause the value of the equilibrium constant to change?
LUCKY_DIMON [66]

According to the Le-chatelier principle,

the equilibrium constant of an system is affected by following three factors:

1.Concentration of reacting substance

2.Temperature to carryout the reaction

3.Pressure provided during the reaction

5 0
4 years ago
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