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marysya [2.9K]
3 years ago
6

If a sample of a gas occupies 5.22 L at 235 oC, what will its volume be at 75 oC if the pressure remains the same?

Chemistry
1 answer:
marin [14]3 years ago
8 0

Answer:

1618.2

Explanation:

235+75=310×75=1618.2

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25.00 gal/min to L/s, Express your answer using four significant figures.
PtichkaEL [24]
Hope this helps you..

6 0
3 years ago
Boyle’s law states that the volume of a gas is inversely proportional to its pressure if the
nasty-shy [4]

Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its temperature if<u> the temperature and the number of particles are constant.</u>

<h3>Further Explanation</h3><h3>Boyles’s law  </h3>
  • This gas law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature.
  • Therefore, when the volume of an ideal gas is increased at constant temperature then the pressure of the gas will also increase.
  • Mathematically;  Volume α 1/Pressure

                               Vα1/P

  • Therefore, constant k, is = PV
<h3>Other gas Laws</h3><h3>Gay-Lussac’s law  </h3>
  • It states that at constant volume, the pressure of an ideal gas I directly proportional to its absolute temperature.
  • Thus, an increase in pressure of an ideal gas at constant volume will result to an increase in the absolute temperature.
<h3>Charles’s law</h3>
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.
  • Therefore, an increase in volume of an ideal gas causes a corresponding increase in its absolute temperature and vice versa while the pressure is held constant.
<h3>Dalton’s law  </h3>
  • It is also known as the Dalton’s law of partial pressure. It states that the total pressure of a mixture of gases is always equivalent to the total sum of the partial pressures of individual component gases.
  • Partial pressure refers to the pressure of an individual gas if it occupies the same volume as the mixture of gases.

Keywords: Gas law, Boyles's law, pressure, volume, absolute temperature, ideal gas

<h3>Learn more about:</h3>
  • Boyles’s law: brainly.com/question/2438000
  • Gay-Lussac’s law: brainly.com/question/2438000
  • Charles’s law:brainly.com/question/2438000
  • Dalton’s law:brainly.com/question/2438000

Level: High school

Subject: Chemistry

Topic: Gas laws

Sub-topic: Boyle's Law  

3 0
3 years ago
Read 2 more answers
Pls assist if you can.<br>Reasons why hydrogen was chosen as a standard reference to other elements
MrMuchimi

Answer:

See below  

Step-by-step explanation:

  • Hydrogen either reacts with or is formed by reactions with many other elements, so chemists could use it directly to determine their relative masses.
  • Hydrogen has the smallest atomic mass, so it was convenient to give H a relative atomic mass of 1 and assign those of other elements as multiples of this number.

The O = 16 scale became the standard in 1903 and carbon-12 was chosen in 1961.

4 0
3 years ago
The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argo
noname [10]

Answer:

<h2>36.09 L</h2>

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

V_1 =  \frac{P_2V_2}{P_1}  \\

We have

V_1 =  \frac{7.98 \times 14.2}{3.14} =   \frac{113.316}{3.14}  \\  = 36.0878...

We have the final answer as

<h3>36.09 L</h3>

Hope this helps you

8 0
3 years ago
4
STALIN [3.7K]

Answer: The space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

Explanation:

Given: V_{1} = 250 mL,    P_{1} = 800 torr,     T_{1} = 50^{o}C

V_{2} = ?,         P_{2} = 400 torr,        T_{2} = 25^{o}C

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL

Thus, we can conclude that space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

7 0
3 years ago
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