Acetone will react with ammonia. Acetone will act as an Lewis Acid and ammonia will act as a Lewis Base in this situation. The nitrogen in NH3 is very reactive because of its lone pair of electrons(The nitrogen is delta -ve), so it will attack the carbon cation center of the acetone (which is delta +ve).
Answer:
11.39
Explanation:
Given that:
![pK_{b}=4.82](https://tex.z-dn.net/?f=pK_%7Bb%7D%3D4.82)
![K_{b}=10^{-4.82}=1.5136\times 10^{-5}](https://tex.z-dn.net/?f=K_%7Bb%7D%3D10%5E%7B-4.82%7D%3D1.5136%5Ctimes%2010%5E%7B-5%7D)
Given that:
Mass = 1.805 g
Molar mass = 82.0343 g/mol
The formula for the calculation of moles is shown below:
![moles = \frac{Mass\ taken}{Molar\ mass}](https://tex.z-dn.net/?f=moles%20%3D%20%5Cfrac%7BMass%5C%20taken%7D%7BMolar%5C%20mass%7D)
Thus,
![Moles= \frac{1.805\ g}{82.0343\ g/mol}](https://tex.z-dn.net/?f=Moles%3D%20%5Cfrac%7B1.805%5C%20g%7D%7B82.0343%5C%20g%2Fmol%7D)
![Moles= 0.022\ moles](https://tex.z-dn.net/?f=Moles%3D%200.022%5C%20moles)
Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)
![Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7BMoles%5C%20of%5C%20solute%7D%7BVolume%5C%20of%5C%20the%5C%20solution%7D)
![Molarity=\frac{0.022}{0.055}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B0.022%7D%7B0.055%7D)
Concentration = 0.4 M
Consider the ICE take for the dissociation of the base as:
B + H₂O ⇄ BH⁺ + OH⁻
At t=0 0.4 - -
At t =equilibrium (0.4-x) x x
The expression for dissociation constant is:
![K_{b}=\frac {\left [ BH^{+} \right ]\left [ {OH}^- \right ]}{[B]}](https://tex.z-dn.net/?f=K_%7Bb%7D%3D%5Cfrac%20%7B%5Cleft%20%5B%20BH%5E%7B%2B%7D%20%5Cright%20%5D%5Cleft%20%5B%20%7BOH%7D%5E-%20%5Cright%20%5D%7D%7B%5BB%5D%7D)
![1.5136\times 10^{-5}=\frac {x^2}{0.4-x}](https://tex.z-dn.net/?f=1.5136%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%20%7Bx%5E2%7D%7B0.4-x%7D)
x is very small, so (0.4 - x) ≅ 0.4
Solving for x, we get:
x = 2.4606×10⁻³ M
pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61
<u>pH = 14 - pOH = 14 - 2.61 = 11.39</u>
The minimum energy required to excite a hydrogen atom from its lowest energy level is 10.2 eV.
<h3>What is excitation?</h3>
The term excitation has to do with the promotion of an electron from a lower to a higher energy level.
In this case, we are dealing with the hydrogen atom having only one electron. Thus, the minimum energy required to excite a hydrogen atom from its lowest energy level is 10.2 eV.
Learn more about energy level:brainly.com/question/17396431
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A. Adding a catalyst. A catalyst by definition is a compound that speeds up reaction rates.