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sukhopar [10]
3 years ago
6

A soccer ball is kicked from the ground with an initial upward velocity of 90 feet per second. The equation h(t) = -16t^2+90t gi

ves the height h of the ball after t seconds
a. How many seconds will it take for the ball to reach its maximum height


b. What is the maximum height of the ball


c. Give the domain and range of the function
Mathematics
1 answer:
natali 33 [55]3 years ago
7 0

Answer:

The ball reaches a height of 126.58 ft after 2.8125 seconds

Step-by-step explanation:

The maximum height of a parabola can always be found by looking for the vertex. You can find the x value (or in this case the t value) of a vertex by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

-(90)/2(-16)

-90/-32

2.8125 seconds

Now to find the height, we input that value in for t

h = -16t^2 + 90t

h = -16(2.8125)^2 + 90(2.8125)

126.58 feet

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Answer:

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First of all, it is convenient to choose the false statement.

We note that statements 7 (Alan is first) and 10 (Alan did not finish) are contradictory, so one of them must be false. Statement 5 has Henry & Hughes together, so is not consistent with statement 7 (Alan & Hughes). So, statement 7 is inconsistent with two other statements, thus must be the false one.

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The attached table shows how we parsed the statements. An "O" signifies a combination that must occur; and "X" signifies one that cannot occur. We have used "-" to fill the spaces that are inconsistent with the locations of "O". The red letters are deduced from the others.

The first complete set we found was Henry & Hughes (Don & Gladstone) who were in the (red) capsized raft and did not finish. The second complete set we found was Phil & Cook (Frank & Hawley) who were in the (yellow) raft that finished second. We know Paul & Wilson (Alan & Partner) finished last, so Phil & Cook could not have been Paul and Wilson. Finally, O'Brien and Leroy were not on the same boat, so Paul must be Paul O'Brien and Leroy must be Leroy Sands.

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3 years ago
<img src="https://tex.z-dn.net/?f=5%5Cfrac%7B42%7D%7B170%7D%20%20-%203%5Cfrac%7B80%7D%7B170%7D%20" id="TexFormula1" title="5\fra
Reika [66]

5\dfrac{42}{170}-3\dfrac{80}{170}=(5-3)+\left(\dfrac{42}{170}-\dfrac{80}{170}\right)\\\\=2+\left(-\dfrac{38}{170}\right)=2-\dfrac{32}{170}=1\dfrac{170}{170}-\dfrac{38}{170}\\\\=1\dfrac{170-38}{170}=1\dfrac{132}{170}=1\dfrac{132:2}{170:2}=1\dfrac{66}{85}


5\dfrac{42}{170}-3\dfrac{80}{170}=4\dfrac{170+42}{170}-3\dfrac{80}{170}\\\\=(4-3)+\left(\dfrac{212}{170}-\dfrac{80}{170}\right)=1+\dfrac{212-80}{170}\\\\=1+\dfrac{132}{170}=1\dfrac{132:2}{170:2}=1\dfrac{66}{85}

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