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Tresset [83]
3 years ago
15

Evaluate 3(x-1)+1 when x=5

Mathematics
2 answers:
Lana71 [14]3 years ago
4 0

3(5-1)+1

(15-3)+1

12+1

13

choli [55]3 years ago
3 0

\huge{\boxed{13}}

Substitute. 3(5-1)+1

Subtract. 3*4+1

Multiply. 12+1

Add. \boxed{13}

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Answer: Choice A

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===============================================

The formula is

Sn = (n/2)*(a1+an)

where

Sn = sum of the first n terms (nth partial sum)

n = number of terms

a1 = first term

an = nth term

In this case,

n = 9

a1 = 2 (plug in n = 1 into the formula an = 3n-1 and simplify)

an = a9 = 26 (plug n = 9 into the formula an = 3n-1 and simplify)

So,

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Step-by-step explanation:

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We now know the height of the triangle and can use this to go back and find the area of the isosceles triangle.

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I'm pretty sure it's A.

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