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3 years ago

Which pair correctly matches the lab equipment with its purpose?

Chemistry

2 answers:

Serjik [45]3 years ago

8 0

The answer would be D. Hope this helps

mafiozo [28]3 years ago

4 0

It's C, I took the test.

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alexdok [17]

Answer:

sounds like neon

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3 years ago

What test would you use to identify a solution of fecl3

uysha [10]

Answer:

Ferric chloride test

Explanation:

The ferric chloride test can be used to detect metabolites in urine in case of inborn error of metabolism such as phenylketonuria. Compounds such as phenylpyruvate increase in plasma and are excreted out via urine. Also, it can be used to detect salicylates in urine, quick diagnostic test for aspirin overdose.

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3 years ago

For the following isotopes that have missing information, fill in the missing information to complete the notation: 34 14X

krok68 [10]

Answer:

For the following isotopes that have missing information, fill in the missing information to complete the notation: 34 14X answer- 34/14 Si

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3 years ago

You are asked to perform an experiment. When you perform the experiment you notice the vessel is warming. What type of reaction

Brut [27]

Exothermic type of reaction is taking place because this type of reaction generates heat energy.

<h3>What is exothermic reaction?</h3>

Exothermic reactions refer to those chemical reactions that produce heat energy and release that heat energy to the surrounding environment.

So we can conclude that exothermic type of reaction is taking place because this type of reaction generates heat energy.

Learn more about reaction here: brainly.com/question/26018275

3 0

2 years ago

1.674×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 86.6 s. Under identical conditions, 1.715×10-

siniylev [52]

<h2>Answer:</h2>

44.06 g/mol

<h3>Explanation:</h3>

We are given;

Number of moles of unidentified gas as 1.674×10^-4 mol
Time of effusion of unidentified gas 86.6 s
Number of moles of Argon gas as 1.715×10^-4 mol
Time of effusion of Argon gas is 84.5 s

We are supposed to calculate the molar mass of unidentified gas

<h3>Step 1: Calculate the effusion rates of each gas</h3>

Effusion rate = Number of moles/time

Effusion rate of unidentified gas (R₁)

= 1.674×10^-4 mol ÷ 86.6 s

= 1.933 × 10^-6 mol/s

Effusion rate of Argon gas (R₂)

= 1.715×10^-4 mol ÷ 84.5 sec

= 2.030 × 10^-6 mol/s

<h3>Step 2: Calculate the molar mass of unidentified gas</h3>

Assuming the molar mass of unidentified gas is x;
We can use the Graham's law of effusion to find x;
According to Graham's law of diffusion;

$\frac{R_{1}}{R_{2}}}=\frac{\sqrt{MM_{Ar}}}{\sqrt{X}}$

But, Molar mass of Argon is 39.948 g/mol

Therefore;

$\frac{1.933*10^-6mol/s}{2.030*10^-6mol/s}}=\frac{\sqrt{39.948}}{\sqrt{X}}$

$0.9522=\frac{\sqrt{39.948}}{\sqrt{X}}$

Solving for X

x = 44.06 g/mol

Therefore, the molar mass of the identified gas is 44.06 g/mol

3 0

4 years ago