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hichkok12 [17]
3 years ago
14

True or False: All cells have different basic chemical composition. * True False

Chemistry
2 answers:
34kurt3 years ago
8 0
True the answer is true lol
allsm [11]3 years ago
6 0
True is the correct answer
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Imagine that you have 100g of water.
laiz [17]

Answer:

Explanation:

So, just find 55 on the solubility side and with your finger just move to the right untill you touch the line you should get in between 46-48. I would go more for 48.

Hope you have a wonderful day!

6 0
3 years ago
If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres, what is the volume of the gas?
iVinArrow [24]

If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres the volume of the gas 1.66 litres.

Explanation:

Data given:

number of moles of the gas = 0.725

temperature = 105 K

pressure = 3.75 atm

volume of the gas =?

R = 0.08206 Latm/mole Kelvin

Applying the ideal gas law to calculate the volume of the given gas:

PV = nRT

rearranging the equation to calculate volume:

V = \frac{nRT}{P}

putting the values in the equation:

V = \frac{0.08206 X 0.725 X 105}{3.75}

V = 1.66 Litres.

At a temperature of 105 K and pressure of 3.75 atm, 0.725 moles of gas occupy 1.66 litres of volume.

6 0
3 years ago
How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the so
expeople1 [14]

Answer:

2.72 grams

Explanation:

Complete question is

You are asked to pre pare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid

(C6H5COOH)

and any amount you need of sodium benzoate

(C6H5COONa)

How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.

Solution

Given

pH of the buffer solution = 4

Concentration of C6H5COOH = 0.02 M

Volume of the buffer solution = 1.50 L

K_a value for benzoic acid is 6.3 * 10^ {-5}

Concentration of sodium benzoate

pH = - log Ka + log \frac{C6H5COONa}{C6H5COOH}

Substituting the given values we get

log \frac{C6H5COONa}{C6H5COOH}  = 4 + log (6.3 * 10^ {-5})\\log \frac{C6H5COONa}{C6H5COOH}  = -0.20\\\frac{C6H5COONa}{C6H5COOH} = 10^{-0.2}\\{C6H5COONa} = 10^{-0.2} * 0.02\\{C6H5COONa} =  0.63 * 0.02\\{C6H5COONa} =  0.0126 M

Number of moles in sodium benzoate

= 0.0126 * 1.5 \\= 0.0189 Mol

Mass of sodium benzoate

0.0189 mol * 144.147 \frac{g}{mol} \\= 2.72 g

3 0
3 years ago
Explain why there would be many more plants in an ecosystem than ape-x consumers. I NEED THIS PLS
dsp73

Answer:

.

Explanation:

.

5 0
3 years ago
Read 2 more answers
What is the name of IBr4?<br> And is it covalent or ionic?
BlackZzzverrR [31]

Answer: The name of the IBr_4 is Iodine tetrabromide and it is a covalent compound.

Explanation:

Inter-halogen compounds are compounds which composed of two different halogen atoms. For example ;ICl_3,IF_5 etc.

The naming is done by first writing the central atom symbol's name followed by the prefix corresponding to the number of atoms of another halogen atom like: Mono for 1, di ,for 2 tri for 3, tetra for 4 , penta for 5 etc. After this name of the another halogen is written with suffix 'ide' in the end.

The name of the IBr_4 is Iodine tetra bromide.

In halogen compounds, the difference in electronegativities is not so large due to which they form covalent compounds by the means of sharing the electrons. Hence the Iodine tetrabromide  covalent compound.

8 0
3 years ago
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