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ludmilkaskok [199]
3 years ago
14

Solve each equation on the interval 0≤ x ≤ 2π. (tanx-1)(secx-1)=0

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0
The equation (tanx-1) (secx-1) = 0 with<span> the interval 0≤ x ≤ 2π.
Set each factor to zero, that is

tan x - 1 = 0
secx - 1 = 0

x for tan are </span>\pi/2, 3\pi/2, 5\pi/2
x for sec are 0 and 2\pi
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