<span>first what's the mass of 1 mole of CH3OH
</span>C = 12
H3 = 3x1 = 3
O = 16
H =1
<span>Total 32g So we know 6.02x10^23 molecules weigh 32g
</span> 1 molecule weighs 32/6.02x10^23 g so 9.38*10^24 <span>molecules weighs
</span>9.38x10^24 x (32/6.02x10^23=<span>505g (to 3 sig figs</span>
B.) "Distillation" <span>would work best to separate a mixture of liquids with different boiling points
Hope this helps!</span>
Balance Chemical Equation,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO
Solving for X,
X = (56 g × 24.7 g) ÷ 88 g
X = 2.26 g ÷ 88 g
X = 0.0257 g of CO
Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
You know that an unlabeled water bottle contains at least some water. You measure the freezing point of the unknown substance and find that it freezes at a temperature lower than 0 degrees Celsius at 1 atmosphere pressure, <span>The substance will have a boiling point that is less than 100 degrees Celsius.</span>
It's A; decomposition reactions involve one reactant becoming 2 or more products.