Answer:
D
Explanation: When you chill a substance when it is mixed with another substance, ( chilled vinegar mixed with sodium bicarbonate will react slower for instance) it reacts slower do to the molecules slowing down when chilled.
The final temperature of the water is determined as 50.55 ⁰C.
<h3>
Final temperature of the water</h3>
The final temperature of the water is determined from the following calculations;
Q = mcΔθ
Δθ = Q/mc
where;
- Q is the amount of energy = 81 kcal = 338904 J
- c is specific heat capacity of water = 4,200 J/kgC
Δθ = 338904 /(3.5 x 4200)
Δθ = 23.05 °C
Final temperature = T₁ + Δθ
Final temperature = 27.5°C + 23.05 °C = 50.55 ⁰C.
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The answer is C but i might be wrong
Answer:
B) PO2
Explanation:
first solve empirical formula
50%of P and 50%of O
- divide each by molecular mass
P. O
50/32. 50/16
1.5. 3.0
- divide both by the smallest
1.5/1.5. 3.0/1.5
1. :. 2
Empirical formula=PO2
Molecular formula=PO2
(PO2)n= 64
(32+(16×2)=64
(32+32)n=64
64n=64
n= 1
Answer:
Kp = 1.41 x 10⁻⁶
Explanation:
We have the chemical equation:
2 A(g) + 3 B(g)⇌ C(g)
In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):
dn= (sum moles products - sum moles reactants)
= (moles C - (moles A + moles B))
= (1 - (2+3))
= 1 - 5
= -4
We have also the following data:
Kc = 63.2
T= 81∘C + 273 = 354 K
R = 0.082 L.atm/K.mol (it is a constant)
Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:
= (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶