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horsena [70]
4 years ago
14

Given that water serves as an environmental thermoregulator, which of the following biomes would you expect to have the most sta

ble temperatures?
a.
temperate forest
b.
grassland
c.
rainforest
d.
aquatic


Please select the best answer from the choices provided
Chemistry
2 answers:
myrzilka [38]4 years ago
8 0

Answer:

D. aquatic

Explanation:

edge 2020

sweet [91]4 years ago
3 0

Answer:

Aquatic.

Explanation:

The temperature regulation is related to presence of water in a particular biome.

a) Temperate forest: This is a biome with a moderate in the moderate climates and is in between the regions of tropics and boreal.

b) grassland : This mainly have long grasses, flowers and herbs.

c) rainforest: They have extreme temperature conditions of high and low due to presence of tress and not water only.

d) aquatic : this biome has water so it will have most stable temperature.

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Salsk061 [2.6K]
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5 0
3 years ago
Calculate the quotient [co32–]/[hco3–] at ph 10.75.
KATRIN_1 [288]

The chemical equation is:

<span>HCO3^    ->  H^+ + CO3^2- </span>

 

We know that the formula for Ka is:
Ka = [H^+][CO3^2-]/[HCO3^-] 


log Ka = log[H^+] + log[CO3^2-]/[HCO3^-] 
pKa = pH - log[CO3^2-]/[HCO3^-] 
log[CO3^2-]/[HCO3^-] = pH - pKa = 10.75 - 10.329 = 0.421 
<span>[CO3^2-]/[HCO3^-] = Antilog (0.421)  = 2.636 </span>

 

Answer:

<span>2.636</span>

3 0
3 years ago
10.0 g of gaseous ammonia and 6.50 g of oxygen gas are introduced into a previously evacuated 5.50 L vessel. If the ammonia and
Shalnov [3]

Answer:

The density is 3g/L

Explanation:

The reaction that occurs in the vessel is:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

10,0g of NH₃ are:

10,0g * \frac{1mol}{17,031g} = 0,587 moles

6,50 g of O₂ are:

6,50g * \frac{1mol}{32g} = 0,203 moles

For a complete reaction of O₂ there are necessaries:

0,203 mol * \frac{4molNH_{3}}{5molO_{2}}= 0,163 moles of NH_{3}

O₂ is limiting reactant. The excess moles of NH₃ are:

0,587 - 0,163 = <em>0,424 moles of NH₃</em>

These moles are:

0,424mol * \frac{17,031g}{1mol} = <em>7,22g of NH₃</em>

Knowing O₂ is limiting reactant, mass of NO and H₂O are:

0,203molO_{2}*\frac{4molNO}{5molO_{2}}*\frac{30,01g}{1molNO} = <em>4,87g of NO</em>

0,203molO_{2}*\frac{6molH_{2}O}{5molO_{2}}*\frac{18,02g}{1molH_{2}O} = <em>4,39g of H₂O</em>

The total mass is: 7,22g + 4,87g + 4,39g = 16,48g ≡ <em>16,5g </em>

<em>-</em><em>The same mass add in the first. By matter conservation law-</em>

As vessel volume is 5,50L, density is:

16,5g/5,50L = <em>3g/L</em>

I hope it helps!

7 0
4 years ago
What type of crystals does iodine, dry ice (CO2) , ice and plastic form?
Elena-2011 [213]
Molecular crystals does iodine, dry ice (CO2) , ice and plastic form. It is becuase<span> is that all four are made of nonmetal elements.Which implies any compounds are made up of molecule.</span>
4 0
3 years ago
In a chemical equation, the new substance that is produced from a chemical reaction is called __________.
aleksandrvk [35]

Answer:

products

Explanation:

yeah the answer is product

6 0
3 years ago
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