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horsena [70]
4 years ago
14

Given that water serves as an environmental thermoregulator, which of the following biomes would you expect to have the most sta

ble temperatures?
a.
temperate forest
b.
grassland
c.
rainforest
d.
aquatic


Please select the best answer from the choices provided
Chemistry
2 answers:
myrzilka [38]4 years ago
8 0

Answer:

D. aquatic

Explanation:

edge 2020

sweet [91]4 years ago
3 0

Answer:

Aquatic.

Explanation:

The temperature regulation is related to presence of water in a particular biome.

a) Temperate forest: This is a biome with a moderate in the moderate climates and is in between the regions of tropics and boreal.

b) grassland : This mainly have long grasses, flowers and herbs.

c) rainforest: They have extreme temperature conditions of high and low due to presence of tress and not water only.

d) aquatic : this biome has water so it will have most stable temperature.

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A wittig reaction occurs when 4-methylbenzaldehyde and benzyltriphenylphosphonium chloride are stirred together at room temperat
GarryVolchara [31]

Answer:

See explanation

Explanation:

The wittig reaction is an organic reaction in which an aldehyde or a ketone reacts with a phosphonium ylide to give an alkene. This phoshonium ylide that participates in the reaction is usually generated insitu in the system by reaction of an alky or aryl triphenylphosphonium halide salt with a base(sodium hydroxide is mostly used).

In this particular reaction 4-methylbenzaldehyde and benzyltriphenylphosphonium chloride were reacted together in the presence of sodium hydroxide and the product with the structure shown in the answer was obtained as the major isomer produced in the reaction.

3 0
4 years ago
The ksp of copper(ii) carbonate, cuco3, is 1.4 × 10-10. calculate the molar solubility of this compound.
mafiozo [28]
As,
                              CuCO₃    ⇆  Cu²⁺  +  CO₃²⁻
So,
                             Kc  =  [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
                             Kc (CuCO₃)  =  [Cu²⁺] [CO₃²⁻]
Or,
                             Ksp  =  [Cu²⁺] [CO₃²⁻]
As,
Ksp  = 1.4 × 10⁻¹⁰
So,
                            1.4 × 10⁻¹⁰  =  [x] [x]
Or,
                             x²  =  1.4 × 10⁻¹⁰ 
Or,
                             x  =  1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
                             x  =  1.18 × 10⁻⁵ mol/L × 123.526 g/mol

                   
         x  =  1.45 × 10⁻³ g/L
3 0
3 years ago
En una estructura de concreto cuyo peso es de 8500 n se apoyo sobre un area de 25cm2,hallar la presion ejercida sobre su base
babymother [125]

Respuesta:

340 N/cm²

Explicación:

Paso 1: Información provista

Peso de la estructura (F): 8500 Newton

Area superficial (A): 25 cm²

Paso 2: Calcular la presión (P) ejercida por la estructura de concreto sobre su base

La presión es igual al cociente entre la fuerza ejercida y la superficie sobre la que se aplica.

P = F/A

P = 8500 N / 25 cm² = 340 N/cm²

5 0
3 years ago
Chemical Quantities "Molar Mass - 2 step" - Wksh #3 Directions: Use dimensional analysis to perform the following calculations.
fomenos

There are about 1.27  × 10^23 molecules present in 13.5 g of SO2.

<h3>What are molecules?</h3>

A molecule is the simplest part of a compound that have independent existence.

Number of moles of sulfur dioxide = 13.5 g/64 g/mol = 0.211 moles

If 1 mole of SO2 contains 6.02 × 10^23 molecules

0.211 moles of SO2 contains 0.211 moles × 6.02 × 10^23 molecules/1 mole

= 1.27  × 10^23 molecules

32 g of sulfur contains 6.02 × 10^23 atoms

x g of sulfur contains  2.23 x 10^23

x = 32 × 2.23 x 10^23 /6.02 × 10^23

x = 11.85 g

6.02 × 10^23 formula units has a mass of AgF = 127 g

x formula units has a mass of  = 42.15 g

x = 6.02 × 10^23 × 42.15/127

x = 2 × 10^23 formula units

6.02 × 10^23 formula units of Fe2O3 has a mass of 160 g

8.83 x 10^23 formula units of Fe2O3 has a mass of 8.83 x 10^23 x 160 g/6.02 × 10^23

x = 235 g

Learn more about formula unit: brainly.com/question/19293051

6 0
2 years ago
How many mols of chlorine are in 120g of chlorine gas
xz_007 [3.2K]

Answer:

Number of moles of chlorine = 3.38 mol

Explanation:

Given data:

Mass of chlorine = 120 g

Moles of chlorine = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of chlorine = 35.5 g/mol

Now we will put the values in formula.

Number of moles = 120 g/ 35.5 g/mol

Number of moles = 3.38 mol

6 0
4 years ago
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