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erma4kov [3.2K]
2 years ago
12

In the following equation, when x=3, what is the value of y? -4x + 3y = 12

Mathematics
2 answers:
deff fn [24]2 years ago
4 0

Answer:

y = 8

Step-by-step explanation:

-4(3) = -12

to get -12 to 12 you need to add 24 to -12 to make it 12.

so 3 (8) = 24

so -12 + 24 =12

Maslowich2 years ago
4 0

[|] Answer [|]

\boxed{Y \ = \ 8}

[|] Explanation [|]

-4x + 3y = 12

Substitute 3 For X:

-4 * 3 + 3y = 12

Multiply The Numbers:

4 * 3 = 12

-12 + 3y = 12

Add 12 To Both Sides:

-12 + 3y + 12 = 12 + 12

Simplify:

3y = 24

3y/3 = 24/3

24 / 3 = 8

Y = 8

\boxed{[|] \ Eclipsed \ [|]}

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Answer:

<h2>x > 3+y</h2>

Step-by-step explanation:

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Answer:

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Given

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Required

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f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

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x = v^\frac{1}{3}

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f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

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F(x) = [v]\limits^{v^\frac{1}{3}}_9

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F(v) = F'(x)

Differentiate F(x) to give:

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F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

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