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2 years ago

Please tell me the answer.. it will mean and help me a lot and give you more points :)

Mathematics

1 answer:

vovikov84 [41]2 years ago

5 0

Step-by-step explanation:

12500 divided by 0.26= liters

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F(1)=-16 f(n)=-29-f(n-1) f(2)=

charle [14.2K]

F(2)=-29-f(1) = -29-(-16)=-13

4 0

2 years ago

Explain how to write an addition sentence for a picture of 4 rows with 3 items in each row

Dahasolnce [82]

The answer would be:
3 + 3 + 3 + 3...
... If you mean what I'm thinking.

:)

3 0

3 years ago

Read 2 more answers

The function f(x)= --x is shown on the graph.

sertanlavr [38]

Answer:

Option (3).

Step-by-step explanation:

Attached figure is the graph of a function,

f(x) = - $\sqrt{-x}$

Since domain of any function is the set of all possible input values of the function,

Therefore, Domain of the function is,

Domain : x ≤ 0 Or (-∞, 0]

And range of the function is the set of all possible output values (y-values) of the function.

Therefore, Range of the function will be,

Range : y ≤ 0 Or (-∞, 0]

Therefore, Domain and range of this function is same.

Option (3) will be the answer.

7 0

2 years ago

Will give 50 points for this answer. Perform the indicated operation. 22 6/7 ∙ 1 1/2

Varvara68 [4.7K]

Answer:

22 $\frac{6}{7}$ × $\frac{11}{2}$ = 125 .71

Step-by-step explanation:

22 $\frac{6}{7}$ × $\frac{11}{2}$

={[ ( 22 × 7) + 6] ÷ 7 } × $\frac{11}{2}$

= $\frac{160}{7}$ × $\frac{11}{2}$

= $\frac{1760}{14}$

= $\frac{880}{7}$

= 125 .71

5 0

2 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis

Licemer1 [7]

Answer:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

7 0

2 years ago