To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.
A counterexample proves something wrong. To disprove "When it rains, it pours," you could give an example of a time when it rains and does not pour. What if it only rains a little? What if it rains frogs? How are you supposed to "pour" frogs? I dunno. This is sort of an open-ended question. I'd go with "It drizzles, but does not pour."
Answer:
DE/AB= DC/AC , 12/AB= 6/11 , AB= 12×11/6=2×11=22 , Sory i can't explain , i bad know english language. or so ABC~CDE because DE||AB=> DE/AB=DC/AC
Answer:
3/4
Area of the small triangle/Area of larger triangle=3/4
Area of the small triangle/Area of larger triangle=(1/2×base of small triangle×length)/(1/2×base of larger triangle×height)
3/4=(1/2×base of small triangle×height)/(1/2×base of larger triangle×height)
Since the length of the triangle are equal the base ratio of the two triangles is the same as area ratio.
Answer:
A or (2x+1)/(x-1)
Step-by-step explanation:
Let's simplify the top of the fraction first.
1. Simplify the numerator.
2x^2 -7x-4=(2x+1)(x-4)
2. Simplify the denominator.
x^2-5x+4=(x-4)(x-1)
Now we have:
((2x+1)(x-4))/((x-4)(x-1))
We see that there is an (x-4) both on the numerator and denominator.
We can remove (x-4) by division.
Doing that, we have:
(2x+1)/(x-1) or A