See photo for worked out solution.
Hope this helps!
It would be an A if i'm correct.
Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as
where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
is the required r
Answer:
See below ~
Step-by-step explanation:
<u>Question 1</u>
⇒ -7x - (8x + 16) = -1
⇒ -7x - 8x - 16 = -1
⇒ -15x = 15
⇒ x = -1
⇒ y = 8(-1) + 16 = 8
⇒ Solution = <u>(-1, 8)</u>
<u></u>
<u>Question 2</u>
⇒ 3x + 4(-3x - 18) = 0
⇒ 3x - 12x - 72 = 0
⇒ -9x = 72
⇒ x = -8
⇒ y = -3(-8) - 18 = 6
⇒ Solution = <u>(-8, 6)</u>
<u>Question 3</u> (not clear)
<u>Question 4</u>
⇒ -8x - 7(6x) = 0
⇒ -8x - 42x = 0
⇒ -50x = 0
⇒ x = 0
⇒ y = 6(0) = 0
⇒ Solution = <u>(0, 0)</u>
<u>Question 8</u>
- 2x - 6y = -14
- y = -5x - 19
⇒ 2x - 6(-5x - 19) = -14
⇒ 2x + 30x + 114 = -14
⇒ 32x = -128
⇒ x = -4
⇒ y = -5(-4) - 19 = 1
⇒ Solution = <u>(-4, 1)</u>
