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Olegator [25]
3 years ago
12

A car travelled a distance of 348 km in 6.0 hours. What was it’s speed in (a) km/h and (b) m/sec?

Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

[(a=58)(b=16)] is the homogeneous mixture

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A sound has 13 crests and 15 troughs in 3 seconds. When the second crest is produced the first is 2cm away from the source? Calc
Yuki888 [10]

Answer:

The wavelength will be 4 cm, frequency will be 4.66 Hz and wave speed is 18.6 cm/sec

Explanation:

Given:

No. of crest = 13

No. of trough = 15

Time = 3 seconds

Hence, 1 crest or 1 trough = \frac{1}{2}\lambda

therefore,

13 C + 15 T = 28(\frac{1}{2}\lambda)

=14\lambda

Time given 3 seconds

  = \frac{3}{14}s

\nu= \frac{14}{3}

\nu= 4.6 Hz \approx 5 Hz

2 cm distance is travelled is time period

\lambda = 4 cm

Again wave will travel in 1 T = 4 cm

wave speed v =\lambda\times\nu

= 4\times\frac{14}{3}

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5 0
3 years ago
What are three effect of force​
Stolb23 [73]

Answer:

1. Can change the state of an object(rest to motion/ motion to rest)

2. May change the speed of an object if it is already moving.

3. May change the direction of motion of an object.

Explanation: A force acting on an object causes the object to change its shape or size, to start moving, to stop moving, to accelerate or decelerate.

6 0
3 years ago
An object moving 20 m/s
yan [13]

Answer:

<u>We are given:</u>

initial velocity (u) = 20m/s

acceleration (a) = 4 m/s²

time (t) = 8 seconds

displacement (s) = s m

<u />

<u>Solving for Displacement:</u>

From the seconds equation of motion:

s = ut + 1/2 * at²

replacing the variables

s = 20(8) + 1/2 * (4)*(8)*(8)

s = 160 + 128

s = 288 m

7 0
3 years ago
Determine the energy in joules of a photon whose frequency is 3.55 x10^17 hz
asambeis [7]
By using the Plancks-Einstein equation, we can find the energy;
E = hf
where h is the plancks constant = 6.63 x 10⁻³⁴
f = frequency = 3.55 x 10¹⁷hz
E = (6.63 x 10⁻³⁴) x (3.55 x 10¹⁷)
E = 2.354 x 10⁻¹⁶J
3 0
3 years ago
An object pulled to the right by two forces has an acceleration of 2.5m/s2. The free-body diagram shows the forces acting on the
Vanyuwa [196]

Answer:

490 N is the correct answer.

Explanation:

8 0
3 years ago
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