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3 years ago

The hydrogen bond between two water molecules arises because water is

1 answer:

8 0

Hydrogen-bonding forms in liquid water as the hydrogen atoms of one water molecule are attracted towards the oxygen atom of a neighboring water molecule; generally, a proton shared by two lone electron pairs. ... This attraction is the basis of the 'hydrogen' bonds.

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Two parallel square metal plates that are 1.5 cm and 22 cm on each side carry equal but opposite charges uniformly spread out ov

Mumz [18]

Answer:

The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

Explanation:

Given that,

Distance =1.5 cm

Side = 22 cm

Electric field = 18000 N/C

We need to calculate the capacitance in the metal plates

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times(22\times10^{-2})^2}{1.5\times10^{-2}}$

$C=0.285\times10^{-10}\ F$

We need to calculate the potential

Using formula of potential

$V=Ed$

Put the value into the formula

$V=18000\times1.5\times10^{-2}\ V$

$V=270\ V$

We need to calculate the charge

Using formula of charge

$Q=CV$

Put the value into the formula

$Q=0.285\times10^{-10}\times270$

$Q=76.95\times10^{-10}\ C$

Here, the charge on both the positive and negative plates

$Q=+76.95\times10^{-10}\ C$

$Q=-76.95\times10^{-10}\ C$

We need to calculate the number of excess electrons are on the negative surface

Using formula of number of electrons

$n=\dfrac{q}{e}$

Put the value into the formula

$n=\dfrac{76.95\times10^{-10}}{1.6\times10^{-19}}$

$n=4.80\times10^{10}\ electrons$

Hence, The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

8 0

3 years ago

Suppose that a constant force is applied to an object with a mass of 12kg, it’s creates an acceleration of 5m/s^2. The accelerat

Klio2033 [76]

Answer:

Mass of second object will be 15 kg

Explanation:

We have given mass of first object = 12 kg

Acceleration $a=5m/sec^2$

According to second law of motion we know that force F = MA

So force $F=12\times 5=60N$

As the same force is applied to the second object of acceleration $a=4m/Sec^2$

So force = ma

$60=m\times 4$

m = 15 kg

So mass of second object will be 15 kg

5 0

3 years ago

A wire carries a current of 10 amps in a direction of 90 degrees with respect to the direction of an external magnetic field of

Oksi-84 [34.3K]

Answer:

15 N

Explanation:

The magnetic force on a piece of current-carrying wire is given by:

$F=ILB sin \theta$

where

I is the current in the wire

L is the length of the piece of wire

B is the magnetic field strength

$\theta$ is the angle between the direction of B and I

In this problem:

I = 10 A

B = 0.3 T

L = 5 m

$\theta=90^{\circ}$

Substituting into the equation, we find

$F=(10 A)(0.3 T)(5 m) sin 90^{\circ}=15 N$

6 0

3 years ago

Can a tank of oxygen gas ever be half empty?

alisha [4.7K]

No. Any amount of gas always expands to completely fill
whatever container it's in.

So, as you take oxygen out of the tank, the pressure of what's
left in the tank certainly becomes less and less, but whatever is
left in the tank always expands and fills the whole tank.

(And then, eventually, when the pressure inside the tank drops
to equal the pressure outside it (atmospheric pressure), you could
cut off the whole top of the tank and nothing more would come out.)

SCUBA divers regularly talk about having a 'full tank', and 'half a tank',
and maybe a 'quarter tank'. But that refers to the amount of time that
the tank can still deliver air to them under water. It's not the amount
of volume inside the tank that's full or empty. The inside of the tank
is always full.

Think about it this way: ==> There's no way to take half of the air
out of a balloon, leaving it half empty and still inflated. Doesn't happen.

7 0

4 years ago

Read 2 more answers

Deer ticks can carry both Lyme disease and human granulocytic ehrlichiosis (HGE). In a study of ticks in the Midwest, it was fou

tiny-mole [99]

Answer:

a)0.024

b)0.148

Explanation:

Let 's represent the set of deer ticks Carrying Lyme disease with L and the set of deer ticks carrying Human Granulocytic Ehrlichiosis with H

Given:

P(L) = 0.16

P(H) = 0.10

P(L n H) = 0.1 ·P( L u H )

Hence, P( L u H) = 10 ·P( L nH)

(a)

Hence. using the equation. P(L U H) = P(L) + P(H) - P(L n H)

Hence, 10 · P(L n H ) = 0.16 + 0.1 - P(L n H )

Hence, 11 · P(L n H) = 0.16 + 0.1 = 0.26

Hence, P(L n H) = 0.26/11=0.024

(b)

We know that condition probability P(H ║ L) = p(L n H)/P(L)

hence, P(H ║ L) =(0.26/11)/0.16 =0.148

3 0

3 years ago