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Lynna [10]
3 years ago
6

The hydrogen bond between two water molecules arises because water is

Physics
1 answer:
Kobotan [32]3 years ago
8 0
Hydrogen-bonding forms in liquid water as the hydrogen atoms of one water molecule are attracted towards the oxygen atom of a neighboring water molecule; generally, a proton shared by two lone electron pairs. ... This attraction is the basis of the 'hydrogen' bonds.
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De donde eres responde y te doy corona
irakobra [83]

soy de texas, united states

8 0
3 years ago
Assume the equation x 5 At3 1 Bt describes the motion of a particular object, with x having the dimension of length and t having
igomit [66]

Answer:

(a) A = m/s^3, B = m/s.

(b) dx/dt = m/s.

Explanation:

(a)

x = At^3 + Bt\\m = As^3 + Bs\\m = (\frac{m}{s^3})s^3 + (\frac{m}{s})s

Therefore, the dimension of A is m/s^3, and of B is m/s in order to satisfy the above equation.

(b) \frac{dx}{dt} = 3At^2 + B = 3(\frac{m}{s^3})s^2 + \frac{m}{s} = m/s

This makes sense, because the position function has a unit of 'm'. The derivative of the position function is velocity, and its unit is m/s.

6 0
3 years ago
.In a bizarre but harmless accident, Superman fell from the top of the Eiffel Tower. How fast was Superman traveling when he hit
ELEN [110]

Answer:

 (7.8) x (9.8 m/s)  =  76.44 m/s

during the time he spent falling.

Since his falling speed was zero when he 'stepped' off of the top,

he hit the ground at  76.44 m/s.

That's about 170 miles per hour.

I'll bet he left one serious crater!

I hope this helps too! :D

Explanation:

4 0
3 years ago
Some compounds, like carbon dioxide, are gaseous at room temperature, while others are solid at room temperature. Why is this?
Vesnalui [34]
The answer of a & b are force of cohesion and force of adhesion
Of rest two answers I don't know 
8 0
3 years ago
Read 2 more answers
Older televisions display a picture using a device called a cathode ray tube, where electrons are emitted at high speed and coll
Len [333]

Answer:

Explanation:

initial velocity v = 2.1  x 10⁷ m/s

acceleration a = 5.1 x 10¹⁵ m /s²

horizontal distance covered = 5.5 x 10⁻² m

time taken to cover horizontal distance =  5.5 x 10⁻² / 2.1  x 10⁷

= 2.62 x 10⁻⁹ s .

b )

vertical distance travelled due to vertical acceleration

= 1/2 a t²

= .5 x 5.1 x 10¹⁵ x (2.62 x 10⁻⁹)²

= 17.5 x 10⁻³ m

4 0
3 years ago
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