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lbvjy [14]
2 years ago
13

Based on the evidence, write a scientific explanation of what type of wave is being exhibited when crowds at stadiums do “the wa

ve.
Physics
1 answer:
Pani-rosa [81]2 years ago
4 0

Answer:

An analogy to these waves can be shown in waves of a crowd. The standard wave we see at the baseball game could be considered a transverse wave because the people are moving perpendicular to the direction of the wave. If the people bump shoulders instead of standing up, this would be a longitudinal wave.

Explanation:

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How is sound produced? Name its three<br>characteristics.​
nydimaria [60]

Answer:

1.loudness

2.pitch

3.shrillness

5 0
4 years ago
A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms.
victus00 [196]

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ e^{-\lambda t}

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ e^{-\lambda_1 t}

For B

N(B) = N(B)₀ e^{-\lambda_2 t}

N(A) = N(B) , for t = 2 h

N(A)₀ e^{-\lambda_1 t} = N(B)₀ e^{-\lambda_2 t}

N(A)₀ e^{-\lambda_1 t} = 5 x N₀(A)  e^{-\lambda_2 t}

e^{-\lambda_1 t} = 5  e^{-\lambda_2 t}

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

Putting t = 2 h , λ₁ = .9 h⁻¹

e^{\lambda_2\times  2} = 5  e^{.9\times  2}

e^{\lambda_2\times  2} = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

6 0
3 years ago
Suppose a logs mass is 5kg .after burning,the mass of the ash is 1kg .explain what may have happened to the other 4kg
BigorU [14]

The "missing" 4 kg may have escaped the scene of the fire in the
form of hot gases, and as particles of soot and ash that were seen
leaving in the form of "smoke". 

5 0
3 years ago
Wich of the following celestial bodies is most likely to have many craters
Ede4ka [16]
Where are the following awnsers?
6 0
3 years ago
When unequal resistors are connected in series across an ideal battery,the same power is dissipated in each one.the potential di
Agata [3.3K]

Answer:

the current flowing in each is the same.

Explanation:

When resistors are connected in series, they are connected in the same branch of the circuit - this means that the same current flows through each resistor.

The other options listed are wrong because:

the same power is dissipated in each one --> false: the power dissipated in each resistor is P=I^2 R, where I is the current and R the resistance, so it depends on the value of the resistance

the potential difference across each is the same.-- > false: this is true in parallel circuits, not series circuits

the equivalent resistance of the circuit is less than that of the smallest resistor.--> false: the equivalent resistance of a series circuit is the sum of the individual resistances: R = R_1 + R_2 + ..., so it is larger than the resistance of the smallest resistance

the equivalent resistance of the circuit is equal to the average of all the resistances. --> false: the equivalent resistance of a series circuit is the sum of the individual resistances: R = R_1 + R_2 + ..., not the average

7 0
3 years ago
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