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Mumz [18]
3 years ago
6

A permanent magnet cannot be used in electrical bell .Why?​

Physics
2 answers:
Zielflug [23.3K]3 years ago
8 0

Answer:

we can not use permanent magnets in radio and electric bells , because permanent magnets loose their property after some time whereas we can change the properties of electromagnet.

sladkih [1.3K]3 years ago
6 0
What he said, yup!! ^^^
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Describe a situation that includes no less than four charges of any magnitude, but they combine so that another location, p, has
Degger [83]

Answer:

Four charges of equal magnitude sitting at the vertices of a square

Explanation:

We can arrive at such a situation by thinking of a simple example first, a configuration of two charges. The force acting on the middle point of a straight line joining the two points(charges) will be zero. That is, the net Electric field will be zero as they cancel out being equal in magnitude and opposite in direction.

Now, we can extend this idea to a square having charge q at each vertex. If we put 'p' at the geometric center, we can see that the Electric fields along the diagonals cancel out due to the charges at the diagonally opposite vertices(refer to the figure attached). Actually, the only requirement is that the diagonally opposite charges are equal.

We can further take this to 3 dimensions. Consider a cube having charges of equal magnitude at each vertex. In this case, the point 'p' will yet again be the geometric center as the Electric field due to the diagonally opposite charges will cancel out.

6 0
2 years ago
Dina has a mass of 50 kilograms and is waiting at the top of a ski slope that’s 5.0 meters high.
Over [174]
All of Dina's potential energy Ep is converted into kinetic energy Ek so Ep=Ek, where Ep=m*g*h and Ek=(1/2)*m*v². m is the mass of Dina, h is the height of ski slope, g=9.8 m/s² and v is the maximal velocity. 

So we solve for v:

m*g*h=(1/2)*m*v², masses cancel out,

g*h=(1/2)*v², we multiply by 2,

2*g*h=v² and take the square root to get v

√(2*g*h)=v, we plug in the numbers and get:

v=9.9 m/s. 

So Dina's maximum velocity on the bottom of the ski slope is v=9.9 m/s.
8 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP!!!
musickatia [10]

Answer:

22.2 W

Explanation:

First of all, we calculate the work done by moving the wagon, using the formula:

W=Fdcos \theta

where

F = 20 N is the magnitude of the force

d = 1000 m is the displacement of the wagon

\theta=0^{\circ} is the angle between the direction of the force and of the displacement (assuming the force is applied in the direction of motion)

Substituting, we find

W=(20)(1000)=20,000 J

Now we can find the power generated, which is equal to the ratio between the work done and the time taken:

P=\frac{W}{t}

where

W = 20,000 J

t = 15 min = 900 s

Substituting,

P=\frac{20000}{900}=22.2 W

And the same value in Joules/second (remember that 1 Watt = 1 Joule/second)

5 0
3 years ago
Which of Newton's laws accounts for the following statement? "A force cannot act alone."
juin [17]
<span>"A force is required to cause motion to deviate from a straight line.</span>
8 0
2 years ago
Read 2 more answers
A student standing on a knoll throws a snowball horizontally 4.5 meters above the level ground toward a smokestack 15 meters awa
Elan Coil [88]

Answer:

2.4 m

Explanation:

Consider the motion along the vertical direction

y_{o} = initial position of ball above the ground = 4.5 m

t = time taken by the ball to hit the smokestack = 0.65 s

v_{oy} = initial velocity of the ball along vertical direction

a_{y} = acceleration due to gravity = - 9.8 m/s²

y = position of ball at the time of hitting the smokestack

Using the kinematics equation

y = y_{o} + v_{oy} t + (0.5) a_{y} t^{2}

inserting the above values

y = 4.5 + (0) (0.65) + (0.5) (- 9.8) (0.65)^{2} \\y = 2.4 m

6 0
3 years ago
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