Answer:
temperature on left side is 1.48 times the temperature on right
Explanation:
GIVEN DATA:

T1 = 525 K
T2 = 275 K
We know that


n and v remain same at both side. so we have

..............1
let final pressure is P and temp 

..................2
similarly
.............3
divide 2 equation by 3rd equation
![\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B11%7D%5E%7B-2%2F3%7D%20%5Cfrac%7B21%7D%7B11%7D%5E%7B5%2F3%7D%20%3D%20%5B%5Cfrac%7BT_1%20%7Bf%7D%7D%7BT_2%20%7Bf%7D%7D%5D%5E%7B5%2F3%7D)

thus, temperature on left side is 1.48 times the temperature on right
Answer:
-56.9 m/s
Explanation:
Given:
Δy = -165 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (-9.8 m/s²) (-165 m)
v = -56.9 m/s
The answer is A because you have to have erosion
Answer:
c. Clockwise
Explanation:
As per FARADAY's the rate of change in magnetic flux linked with a coil will induce EMF in the coil and this will result the induce current in the coil.
Here we know that the direction of induced current in the closed loop is in such a way that the magnetic flux due to induced current always oppose the flux due to which it is induced
So we can say that if the flux linked with the coil will increase with time then flux of induced current will be in opposite direction to oppose the increasing flux.
So here when magnetic field becomes stronger then the induced current is in such a way that will always oppose the increasing flux of magnetic field
So we will say that correct answer will be
c. Clockwise
Answer:
The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m
Explanation:
R= 0.2 Ω
L= 0.8 m
S= 1.5mm*2mm= 3 mm² = 3 * 10⁻⁶ m²
ρ = (R*S)/L
ρ= 7.5 * 10⁻⁷ Ω.m