Answer:
20.27 km
Step-by-step explanation:
14.47
+ <u> 5.8</u>
<u> </u> 20.27
Answer:
The mentioned number in the exercise is:
Step-by-step explanation:
To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.
If:
- x = hundredths digit
- y = tens digit
- z = ones digit
We can write:
- x = z + 1 (the hundreds digit is one more than the ones digit).
- y = 2x (the tens digit is twice the hundreds digit).
- x + y + z = 11 (the sum of the digits is 11).
Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:
- x + y + z = 11
- (z + 1) + y + z = 11 (remember x = z + 1)
- z + 1 + y + z = 11
- z + z +y + 1 = 11 (we just ordered the equation)
- 2z + y + 1 = 11 (z + z = 2z)
- 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
- 2z + y = 10
- 2z + (2x) = 10 (remember y = 2x)
- 2z + 2x = 10
- 2z + 2(z + 1) = 10 (x = z + 1 again)
- 2z + 2z + 2 = 10
- 4z + 2 = 10
- 4z = 10 - 2
- 4z = 8
- z = 8/4
- <u>z = 2</u>
Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:
- x = z + 1
- x = 2 + 1
- <u>x = 3</u>
And we'll use the second equation to obtain the value of y (the tens digit):
- y = 2x
- y = 2(3)
- <u>y = 6</u>
Organizing the digits, we obtain the number:
- Number = xyz
- <u>Number = 362</u>
As you can see, <em><u>the obtained number is 362</u></em>.
Answer:
sure where is the attachment?
Step-by-step explanation:
Answer:
The answer is "(0.461 , 7.206)"
Step-by-step explanation:
In the given question some information is missing, that is data. so, the correct answer to this question can be defined as follows:
UnLogged:
![x_1=17.500\\s_1=3.529\\n_1=12](https://tex.z-dn.net/?f=x_1%3D17.500%5C%5Cs_1%3D3.529%5C%5Cn_1%3D12)
Logged:
![x_2=13.667\\ s_2=4.500\\n_2=9\\](https://tex.z-dn.net/?f=x_2%3D13.667%5C%5C%20s_2%3D4.500%5C%5Cn_2%3D9%5C%5C)
formula of std error:
![\ std \ error =\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}](https://tex.z-dn.net/?f=%5C%20std%20%5C%20error%20%3D%5Csqrt%7B%5Cfrac%7Bs_1%5E2%7D%7Bn_1%7D%2B%5Cfrac%7Bs_2%5E2%7D%7Bn_2%7D%7D)
![=\sqrt{\frac{3.529^2}{12}+\frac{4.500^2}{9}}\\\\=\sqrt{\frac{3.529^2\times 3+4.500^2\times 4}{36}}\\\\=1.8133](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%5Cfrac%7B3.529%5E2%7D%7B12%7D%2B%5Cfrac%7B4.500%5E2%7D%7B9%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%5Cfrac%7B3.529%5E2%5Ctimes%203%2B4.500%5E2%5Ctimes%204%7D%7B36%7D%7D%5C%5C%5C%5C%3D1.8133)
Point differential estimation =![x_1-x _2](https://tex.z-dn.net/?f=x_1-x%20_2)
![= 17.500-13.667\\=3.833](https://tex.z-dn.net/?f=%3D%2017.500-13.667%5C%5C%3D3.833)
For 90 percent t= 1.860 Cl & 8 df
error of margin E = ![t\times \ std \ error](https://tex.z-dn.net/?f=t%5Ctimes%20%5C%20std%20%5C%20error)
![= 1.860 \times 1.8133\\= 3.373](https://tex.z-dn.net/?f=%3D%201.860%20%5Ctimes%201.8133%5C%5C%3D%203.373)
Lower bound =mean difference -E=0.461
Upper bound = mean difference+ E=7.206
In the above 90% confidence interval were the population mean= (0.461 , 7.206)