Answer:
0.9985
Step-by-step explanation:
The population standard deviation is:
s² = 64
s = 8
The sample standard deviation is:
σ = s/√n
σ = 8/√39
σ = 1.28
The z-score is:
z = (x − μ) / σ
z = (128.2 − 132) / 1.28
z = -2.97
The probability is:
P(Z > -2.97) = 1 − P(Z < -2.97)
P(Z > -2.97) = 1 − 0.0015
P(Z > -2.97) = 0.9985
Answer:
(x-1)3
3x-3
Step-by-step explanation:
I came up with this.
Answer:
![x = 5](https://tex.z-dn.net/?f=x%20%3D%205)
Step-by-step explanation:
![7x+16x-56=59](https://tex.z-dn.net/?f=7x%2B16x-56%3D59)
![23x -56 = 5 9](https://tex.z-dn.net/?f=23x%20-56%20%3D%205%209)
![2 3 x - 5 6 + 5 6 = 5 9 + 5 6](https://tex.z-dn.net/?f=2%203%20x%20-%205%206%20%2B%205%206%20%3D%205%209%20%2B%205%206)
![23x=115](https://tex.z-dn.net/?f=23x%3D115)
![\frac{23x}{23} = \frac{115}{23}](https://tex.z-dn.net/?f=%5Cfrac%7B23x%7D%7B23%7D%20%3D%20%5Cfrac%7B115%7D%7B23%7D)
![x = 5](https://tex.z-dn.net/?f=x%20%3D%205)
<h3>
Answer: Choice B</h3>
===================================================
Explanation:
The idea is that for any term, we add on the common difference d to get the next term. For example, the sequence {3, 7, 11, 15, 19, 23, ...} has us add on 4 each time so d = 4 in this case.
3+4 = 7
7+4 = 11
11+4 = 15
and so on. The nth term is represented by the notation
while the term just before the nth term is written as ![a_{n-1}](https://tex.z-dn.net/?f=a_%7Bn-1%7D)
So adding d onto the term just before the nth term gets us the nth term which is how we end up with ![a_n = a_{n-1}+d](https://tex.z-dn.net/?f=a_n%20%3D%20a_%7Bn-1%7D%2Bd)
This is the recursive form of the arithmetic sequence. The closed form is written as ![a_n = a_1 + d(n-1)](https://tex.z-dn.net/?f=a_n%20%3D%20a_1%20%2B%20d%28n-1%29)
Answer:
Step-by-step explanation:
58 and 41 are the numbers