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Westkost [7]
3 years ago
11

Write the word sentence as an equation. Then solve.

Mathematics
2 answers:
ELEN [110]3 years ago
7 0
P-6=-14 p is -8 .
+6=+6 hope this helps (:
—— —
p = -8
Burka [1]3 years ago
6 0

Answer: EQUATION: p-6=-14 ANSWER: p=-8

Step-by-step explanation:

Just simply add 6 to both sides so p can be by by itself. -14+6=-8

Hope this helped you! ^_^

You might be interested in
Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has
Feliz [49]

Answer:

16 sweets

Step-by-step explanation:

Number of sweet that Sekhar had = x

Sweets given to Renu = (1/4) of x = \frac{1}{4}x

Sweets given to Raji = 5

Remaining sweets = 7

x = \frac{1}{4}x +5 + 7\\\\x -\frac{1}{4}x = 12\\\\\frac{4*x}{1*4}x-\frac{1}{4}x = 12\\\\\frac{4x}{4}-\frac{1}{4}x= 12\\\\\frac{3x}{4}=12\\\\x = 12*\frac{4}{3}\\\\x=4*4\\\\x=16

6 0
2 years ago
Find an expression equivalent to 1-sinx ^2/1-cosx ^2
madam [21]

Answer:

cot²x

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1, then

1 - sin²x = cos²x

1 - cos²x = sin²x

Thus

\frac{1-sin^2x}{1-cos^2x} = \frac{cos^2x}{sin^2x} = cot²x

8 0
3 years ago
Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.
melamori03 [73]

Answer:

a) 0.8413

b) 421

c) P_{95} = 189.675

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of  IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(IQ scores at most 180)

P(x < 180)

P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 180) = 0.8413 = 84.13\%

b) Number of the members of the club have IQ scores at most 180

n = 500

\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95  

Calculation the value from standard normal z table, we have,  

P(z < 1.645) = 0.95

\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675  

P_{95} = 189.675

8 0
3 years ago
Kathy swam 3 laps in the pool this week. She must swim more than 12 laps.
Marysya12 [62]

Answer:10

Step-by-step explanation:

7 0
3 years ago
The length of a swimming pool is 4 feet longer than 2 times its width. If the perimeter of the pool is 128 feet, what is the wid
alexandr1967 [171]
P = 2(L + W)
P = 128
L = 2W + 4

128 = 2(2W + 4 + W)
128 = 2(3W + 4)
128 = 6W + 8
128 - 8 = 6W
120 = 6W
120/6 = W
20 = W <=== width is 20 ft

L = 2W + 4
L = 2(20) + 4
L = 40 + 4
L = 44 <=== length is 44 ft
5 0
4 years ago
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