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viva [34]
2 years ago
6

rmula1" title="p^{2} +6p=q^{2}+6q.\\p\neq q.\\Solve for p+q." alt="p^{2} +6p=q^{2}+6q.\\p\neq q.\\Solve for p+q." align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Rainbow [258]2 years ago
5 0

Answer:

p + q = -6

Step-by-step explanation:

p^{2} + 6 p = q^{2} + 6q \\p^{2} - q^{2} = 6q - 6p

( p + q) ( p-q) = 6 ( q - p )

p + q = \frac{6 ( q - p)}{(p-q)}  \\p + q = \frac{-6( p - q)}{(p - q)} \\p + q = -6

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3 years ago
What is the y=Mx+b of this equation
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Answer:

y =  - 6x - 8

Step-by-step explanation:

The y-intercept is where the line itersects the y-axis, which is the dark vertical line. This is -8 represented as the constant in the equation.

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Answer:

Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

37210       38015       −805

48360     47800        560

38200    37810          390

33500    33215        285

Sum of difference = 2532+ 3664+740+150 −805+  560 +390 +285 = 7516

Mean = d=\frac{7516}{8}

Mean = d=939.5

a) d= 939.5

\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, t_{\frac{\alpha}{2}}=3.499

Formula for confidence interval = \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)

Substitute the values

confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

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