<img src="https://tex.z-dn.net/?f=p%5E%7B2%7D%20%2B6p%3Dq%5E%7B2%7D%2B6q.%5C%5Cp%5Cneq%20q.%5C%5CSolve%20for%20p%2Bq." id="TexFo

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3 years ago

rmula1" title="p^{2} +6p=q^{2}+6q.\\p\neq q.\\Solve for p+q." alt="p^{2} +6p=q^{2}+6q.\\p\neq q.\\Solve for p+q." align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Rainbow [258]3 years ago

5 0

Answer:

$p + q = -6$

Step-by-step explanation:

$p^{2} + 6 p = q^{2} + 6q \\p^{2} - q^{2} = 6q - 6p$

$( p + q) ( p-q) = 6 ( q - p )$

$p + q = \frac{6 ( q - p)}{(p-q)} \\p + q = \frac{-6( p - q)}{(p - q)} \\p + q = -6$

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