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sattari [20]
3 years ago
5

Find the volume of each figure

Mathematics
1 answer:
pshichka [43]3 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

1. The first figure shows triangular prism. The volume of the triangular prism is

V=\text{Base area}\times \text{Height}

The base of this triangular prism is the triangle with the base of 7 cm and height of h cm (it is not seen).

The base area is

\text{Base area}=\dfrac{1}{2}\times \text{Base}\times \text{Height}=\dfrac{1}{2}\times 7\times h=\dfrac{7h}{2}\ cm^2

and the volume of the prism is

V=\dfrac{7h}{2}\times 13=\dfrac{91h}{2}\ cm^3

Just substitute the length of the height and calculate the volume.

2. The second figure shows square pyramid. The volume of the square pyramid is

V=\dfrac{1}{3}\times \text{Base area}\times \text{Height}

The base of this square pyramid is the square with the side length of 4 yd.

The base area is

\text{Base area}= \text{Side Lenght}^2=4^2 =16\ yd^2

and the volume of the pyramid is

V=\dfrac{1}{3}\times 16\times 12=64\ yd^3

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3 years ago
there are 148 juniors and 272 seniors attending prom this year. if there must be three chaperones per 60 students, how many chap
valkas [14]

21 chaperones are needed for 420 students.

Step-by-step explanation:

No. of juniors = 148

No. of seniors = 272

Total = 148+272 = 420 students

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1 chaperone = \frac{60}{3}=20\ students

Ratio of chaperon to students = 1:20

Let,

x be the number of chaperons for 420 students.

Ration of chaperones to students = x:420

Using proportion

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Product of mean = Product of extreme

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Dividing both sides by 20

\frac{20x}{20}=\frac{420}{20}\\x=21

21 chaperones are needed for 420 students.

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

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