6(x^2-1)(6x-1/6(x+1))
On factoring (x^2-1)=(x+1)(x-1)
= 6(x-1)(x+1)(6x-1/6(x+1))
Cancelling (x+1) from numerator and denominator we get,
= 6(x-1)(6x-1)/6
Cancelling 6 we get,
= (x-1)(6x-1)
Step-by-step explanation:
my name is my name is mikiyas
15 because in the table 10=12.50 so to find how much 1 is you have to move the decimal one place to the left (1.25). Then you have to do 1.25x12 which gives you 15. Hope this helps!
Third option is your answer
Answer:
2√10
Step-by-step explanation:
Given the coordinates (-6, 2) and (0,0)
We are to find the distance between the coordinates. Using the distance formula;
d = √(x2-x1)²+(y2-y1)²
d = √(0-2)²+(0+6)²
d = √(-2)²+(6)²
d = √4+36
d = √40
d = √4*10
d = 2√10
Hence the required distance is 2√10