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3 years ago

Can anyone help me on this geometry question and explain it?

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

Answer:

The length of FG is 5.

Step-by-step explanation:

We can use the distance formula to solve.

D = $\sqrt{ (x2 - x1)^{2} + (y2 - y1)^{2} }$

D = $\sqrt{ (1 - -2)^{2} + (0 - -4)^{2} }$

D = $\sqrt{ 3^{2} + 4^{2} }$

D = $\sqrt{ 9 + 16 }$

D = $\sqrt{25}$

D = 5

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Step-by-step explanation:

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3 years ago

Which problem could be solved by evaluating the expression 4×(−6)?

natima [27]

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3 years ago

Read 2 more answers

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$