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3 years ago

10

Consider the formation of the three solutionsshown in the table.

1 answer:

bazaltina [42]3 years ago

8 0

Answer:

sorry please can you snap the diagram ...the question is not clear to my understanding

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Which subatomic particle adds atomic mass to an atom but without adding charge? A. ion B. proton C. electron D. neutron

alexandr1967 [171]

Neutron is the answer, it has no charge

4 0

4 years ago

Read 2 more answers

If you can answer as many of these as possible that would be great, will give thanks, 5 stars, and brainliest :)

alexandr1967 [171]

Answer:

The nucleus of the atom as suggested by "nuclear" chemistry.
Radioactive element are generally very large due to both their high number of protons, neutrons, and electrons.
An excessive amount of protons or neutrons.
Periodic table, table O, and table N.
Personal opinion question.
The atomic number.
It represents the number of protons, and can also represent the number of electrons in a neutral atom (an atom with no charge).
Protons ---- element.
Random, self-generated.
Gamma radiation is the only thing on table O that is mass less. Close to being the same is Beta particles which have almost no mass.
Neutrons and Gamma radiation.
Gamma radiation.
Electrons and Beta particles.
To turn one element into the isotope of another. Yes, I believe it is aptly named because you are changing the identity of the element.
The number of protons because they are what define the identity of an element.

Goodluck!

3 0

3 years ago

Match the terms to their definition.

morpeh [17]

Answer:

2

Explanation:

3 0

3 years ago

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7) For the reaction 9A (g) + B (g)  5C(g) + 1/6 D (g), it takes 4 and a half minutes for the concentration of C to increase to

viva [34]

Answer: The correct option is, (C) 0.53

Explanation:

The given chemical reaction is:

$9A(g)+B(g)\rightarrow 5C(g)+\frac{1}{6}D(g)$

The rate of the reaction for disappearance of A and formation of C is given as:

$\text{Rate of disappearance of }A=-\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}$

Or,

$\text{Rate of formation of }C=+\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

where,

$\Delta C$ = change in concentration of C = 1.33 M

$\Delta t$ = change in time = 4.5 min

Putting values in above equation, we get:

$\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}=\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{1.33M}{4.5min}$

$\frac{\Delta [A]}{\Delta t}=0.53M/min$

Thus, the decrease in A during this time interval is, 0.53

5 0

3 years ago

Calculate the amount of heat (in J) needed to raise the temperature of 3.50 g of water from 22.4oC to 98.8oC.

Anna35 [415]

Answer:

76.4oC or 169.52oF

Explanation:

That's the amount of heat needed

4 0

3 years ago