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Otrada [13]
3 years ago
5

How can you find a tutor??​

Chemistry
2 answers:
jarptica [38.1K]3 years ago
8 0

Answer:

You can find tutors in many ways maybe you can find some apps or

you can also ask any family members who live close and ask them there is many ways :)

It sometimes depends on the subject

Can I have brainliest pleasee

yanalaym [24]3 years ago
7 0

Depending on what you are doing, virtual, or in school, you can contact your school and you ask them, or you can have your teacher, based on the subject, tutor you.

<3

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Calculate the mass in grams for each of the following liquids.
WITCHER [35]
The density is calculated as mass per volume, so if we want to solve for mass, we would multiply density by volume.
For Part A: if we have a density of 0.69 g/mL, and a volume of 280 mL, multiplying these will give a mass of: (0.69 g/mL)(280 mL) = 193.2 g. Rounded to 2 significant figures, this is 190 g gasoline.
For Part B: if we have a density of 0.79 g/mL, and a volume of 190 mL, multiplying these will give a mass of: (0.79 g/mL)(190 mL) = 150.1 g. Rounded to 2 significant figures, this is equal to 150 g ethanol.
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2 years ago
How many neutrons does element X have if its atomic number is 35 and its mass number is 76?
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What keeps the planets in orbit in our solar system
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Read 2 more answers
What is the final volume (L) of a 1.00 L system at 315 K and 1.10 atm if STP conditions are established?
LenaWriter [7]

Answer:

0.95L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 1L

T1 (initial temperature) = 315K

P1 (initial pressure) = 1.10 atm

T2 (final temperature) = stp = 273K

P2 (final pressure) = stp = 1atm

V2 (final volume) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:

P1V1/T1 = P2V2/T2

1.1 x 1/315 = 1 x V2/273

Cross multiply to express in linear form.

315 x V2 = 1.1 x 273

Divide both side by 315

V2 = (1.1 x 273) /315

V2 = 0.95L

Therefore, the final volume of the system if STP conditions are established is 0.95L

5 0
2 years ago
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