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4 years ago

Please help :) it would be appreciated! thanks!

Mathematics

2 answers:

Paha777 [63]4 years ago

7 0

I think it’s Function

docker41 [41]4 years ago

5 0

Step-by-step explanation:

It would be Function..

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Need help with courseReplace 250 with 575 and -3 with -5.

Svetlanka [38]

Given

The demand function

$p(x)=\frac{250}{\sqrt{x}}-5$

To determine:

a) The revenue function.

b) The marginal revenue.

c) The marginal revenue when x=200.

d) The equation of tangent, and its derivation.

Explanation:

It is given that,

$p(x)=\frac{250}{\sqrt{x}}-5$

a) The revenue function is given by,

$\begin{gathered} R(x)=x\cdot p(x) \\ R(x)=x\times(\frac{250}{\sqrt{x}}-5) \\ R(x)=250\sqrt{x}-5x \end{gathered}$

b) The marginal revenue function is,

$\begin{gathered} R^{\prime}(x)=\frac{d}{dx}(R(x)) \\ =\frac{d}{dx}(250\sqrt{x}-5x) \\ =250\times(\frac{1}{2}\times x^{-\frac{1}{2}})-5 \\ =\frac{125}{\sqrt{x}}-5 \end{gathered}$

c) The marginal revenue when x=200 is,

$\begin{gathered} R^{\prime}(200)=\frac{125}{\sqrt{200}}-5 \\ =\frac{125}{10\sqrt{2}}-5 \\ =8.8388-5 \\ =3.8388 \\ =3.84 \end{gathered}$

Hence, the marginal revenue is 3.84.

d) Let y=mx+c is the tangent.

Then,

$y=3.84x+c$

That implies, for y=12.68, and x=200,

$\begin{gathered} 12.68=3.84\times200+c \\ 12.68=768+c \\ c=12.68-768 \\ c=-755.32 \end{gathered}$

Hence, the equation of tangent is,

$y=3.84x-755.32$

8 0

1 year ago

Can someone help me this?:(

Fofino [41]

Answer:

1. 1, 2, 3, 4

2. A

3. empty set

4. I

5. A

6. O

7. I

8 E and O

9. A

10. I

11. U

12. U

4 0

3 years ago

A machine is used to fill containers with a liquid product. Fill volume can be assumed to be normally distributed. A random samp

motikmotik

Answer:

There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.

Step-by-step explanation:

Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

We find mean = 11.015

Sample std deviation = 3.157

a) $H_0: \bar x= 12 oz\\H_a: \bar x >12$