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Dvinal [7]
3 years ago
8

Solve the equation 5x = 7 for x. Give an exact solution as a logarithm, and an

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

fraction x=7/5

mixed number x= 1 2/5

decimal x=1.4

Step-by-step explanation:

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If the standard deviation for a Poisson distribution is known to be 3.60, the expected value of that Poisson distribution is
Charra [1.4K]

Answer: 12.96

Step-by-step explanation:

given data:

Poisson distributio = 3.60

solution:

The Poisson distribution expected value is same as Variance.

which is expressed as = SD^2

therefore;

the expected value

= SD^2

= 3.60^2

= 12.96

5 0
3 years ago
I need help on 11-16
alisha [4.7K]
I cant see all of 11 and 14
12:
3f = 18 \\   \frac{3f}{3}  =  \frac{18}{3}  \\ f = 6
13:
3f =  {3}^{2}  \\ 3f = 9 \\  \frac{3f}{3}  =  \frac{9}{3}  \\ f = 3
15:
3h = 9 + 10 \\ 3h = 19 \\  \frac{3h}{3}  =  \frac{19}{3}  \\ h = 6.3
16:
3f = 27 - 21 \\ 3f = 6 \\  \frac{3f}{3}  =  \frac{6}{3}   \\ f = 2
6 0
3 years ago
Olivia's team played 8 games of basketball. During those 8 games her team's score was: 70, 67, 79, 66, 64, 80, 64 and 75. Find t
castortr0y [4]

Answer:

70.6

Step-by-step explanation:

The mean is the average of a set of numbers.

To find it, add up all the terms and divide it by the number of terms.

70 + 67 + 79 + 66 + 64 + 80 + 64 + 75 = 565

565 / 8 = 70.625

Rounding this to the nearest tenth, we get an answer of 70.6

5 0
2 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
3 years ago
The width of a rectangle is 3cm less than the length. What is the length of the width is 11 cm ?
sukhopar [10]

the answer is 14 cm.i have to write more to post this answer.

7 0
3 years ago
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