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Ivan
2 years ago
6

A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high sch

ool seniors. The study found that the mean SAT score was 516 with a margin of error of 20. Write a confidence interval for the true mean SAT score of the graduating high school seniors.
Mathematics
1 answer:
natali 33 [55]2 years ago
7 0

A confidence interval for the true mean SAT score of the graduating high school seniors will be (496; 536)

<h3>What is a confidence interval?</h3>

A confidence interval (CI) is a range of estimates for an unknown parameter in frequentist statistics.

Mean score ± margin of error

Margin of Error = 20

Mean SAT score = 516

Hence,the confidence interval will be:-

=  516   ±  20

Lower boundary  =  516   -   20  = 496

Upper boundary  =  516   +  20  =  536

To know more about confidence intervals follow

brainly.com/question/16974109

#SPJ1

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Step-by-step explanation:

The formula for Direct Variation is y=kx or k=y/x. In this case I would use k=y/x. If you're y is 8 and x is 3, this means that K=8/3. Using this, we know that X=15. We have to find a Y value so that the fraction with an x of 15 simplified is 8/3. To do this you would write 8/3 and y/15. Now cross multiply to get 3y=120. Divide by 3 to get y=40. View my attachment for the work!

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