Y=ax²+bx+c
c is x-int =7 (0,7), so c=7
vertex=(-3,-2), another point (-6,7)
y=ax²+bx+7
-2=a(-3)²+b*(-3)+7, -2=9a-3b+7, ----> -9=9a-3b ---->-3=3a-b
7=a*(-6)²+b(-6)+7, ---> 0=36a-6b, ---> 0=6a-b
-3=3a-b
0=6a-b ----> b=6a
substitute b=6a in -3=3a-b, so
-3=3a-6a, ----> -3= -3a, a=1
substitute a=1, in b=6a, ---> b=6*1=6
y=ax²+bx+c
y=x²+6x+7
<span>10(cos(4pi/3) + i sin(4pi/3))
To multiply complex numbers in trigonometric form, you simply multiply the radii and add the thetas. We have:
z1=5(cos(pi/2)+i sin(pi/2))
z2=2(cos(5pi/6)+i sin(5pi/6))
The radii for the above 2 numbers are 5 and 2. So the result will have a radius of 5*2 = 10. The thetas are pi/2 and 5pi/6, so the new theta will be pi/2 + 5pi/6 = 3pi/6 + 5pi/6 = 8pi/6 = 4pi/3. So the answer is:
10(cos(4pi/3) + i sin(4pi/3))</span>
Answer:
2.5
Step-by-step explanation:
You can add 9+1 then make ten and add 10 +1