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Crank
3 years ago
5

How can you show that two objects are proportional with a table

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
You can wright them as fractions reduce them and then compare them
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Mrs. Smith paid $6.60 for a dozen donuts. What is the cost per donut in dollars and cents?​
Mekhanik [1.2K]

Answer:

$1.81

Step-by-step explanation:

Dozen donuts cost 6.60 dollars

You will divide 12 by 6.60

you will get 1.81

8 0
3 years ago
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Ow many significant figures are in the number 0.0040090?
Bumek [7]

5 significant figures but note that 0 is only non-significant when it begins a decimal its only significant when it's in between numbers or after a number

7 0
3 years ago
To solve the system of equations below, Grace isolated the variable y in the
yulyashka [42]

Answer:

D

Step-by-step explanation:

2y=10x

Divide both sides by 2.

y=5x

Now substitute this into the second equation.

6 0
3 years ago
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She has 49 packs of red balloons,66 packs of blue balloons and 35 packs of yellow balloons. Each pack contained 12 balloons. She
Mars2501 [29]

Answer:

63

Step-by-step explanation:

just multiply all all the packs by 12 an then subtract 225 and then u divide that by 25 and u get 63

5 0
3 years ago
Find an equation of the line passing through the pair of points. Write the equation in the form Ax +By = C.
Alexxandr [17]

9514 1404 393

Answer:

  5x -y = -37

Step-by-step explanation:

One way to find the coefficients A and B is to use the differences of the x- and y-coordinates:

  A = Δy = y2 -y1 = 2 -(-3) = 5

  B = -Δx = -(x2 -x1) = -(-7 -(-8)) = -1

Then the constant C can be found using either point.

  5x -y = 5(-7) -2 = -37

The equation of the line is ...

  5x -y = -37

_____

<em>Additional comment</em>

This approach comes from the fact that the slope of a line is the same everywhere.

  \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\Delta y}{\Delta x}\\\\\Delta x(y-y_1)=\Delta y(x-x_1)\qquad\text{cross multiply}\\\\\Delta y(x-x_1)-\Delta x(y-y_1)=0\qquad\text{subtract y term}\\\\\Delta y(x) -\Delta x(y) = \Delta y(x_1)-\Delta x(y_1)\qquad\text{Ax+By=C form}

The "standard form" requires that A be positive, so we chose point 1 and point 2 to make sure that was the case.

5 0
2 years ago
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