How can you show that two objects are proportional with a table

GEOMETRY HELP ASAP I'M FAILING. I did the first half now i cant figure this out!!?

Shalnov [3]

OK, so;
BDE and BED are congruent because the opposite sides are both congruent
To find BDE and BED you must subtract 66 degrees from 180 degrees.
You are then left with 114 as the sum of both the angles you need to find
Since they are congruent, all you need to do is divide by two
114/2=57 degrees for both BDE (a) and BED(b)
Now for angle A and C;
This is easy because they are both congruent to the first two!
So basically, all of question four is "57 degrees"
Sadly for number 5 i did not understand the question :"(
For 6 tho;
AC is parallel to DE because angle C is congruent to angle BED
All the others can be ruled out
For 7;
BD is half the length of AE, so:
4x+20=2(3x+5)
4x+20=6x+10
20=2x+10
10=2x
x=5
This means BD is 20 bc
3(5)+5
15+5
20
And AE is 40 bc
20X2=40
or...
4(5)+20

5 0

2 years ago

Bill wanted to try out different water craft he went 62 mikes downstream in a motor boat and 27 mikes down stream on a jest ski

valina [46]

Answer:

The speed on motorboat is 20 mph

Step-by-step explanation:

here, we want to find the speed on the motorboat

if he has a speed of x mph on the motor boat, his speed on the ski will be (x + 10) mph

The total hours is 4 hours

Mathematically; speed = distance/time

Time on ski is 27/x+ 10

Time on motor boat is 62/x

The addition of both is 4

Thus;

27/(x + 10) + 62/x = 4

27(x) + 62(x + 10) = 4(x)(x + 10)

27x + 62x + 620 = 4(x^2 + 10x)

89x + 620 = 4x^2 + 40x

4x^2 -49x-620 = 0

using the quadratic formula;

{-b ± √(b^2-4ac)}/2a

where a = 4, b = -49 and c = -620

= 49 ± √(-49)^2-4(4)(-620)/8

So we have

49+ 111/8 or 49-111/8

Speed cannot be negative

(49 + 111)/8

= 20 mph

3 0

2 years ago

46 out of 200 dogs are short haired breeds. What percent of dogs are not short haired breeds

Ivahew [28]

Hi!

46 out of 200 are short haired, which means that 200 - 46 = 154 out of 200 are not short haired. In percentages, that is:

154/200 = 77/100 = 77%

Hope this helps!

8 0

3 years ago

Bo and Brica are yoga instructors. Between the both of them, they teach 46 yoga classes each week. If Brica teaches 11 fewer tha

PtichkaEL [24]

Bo teaches 19 classes and Brica teaches 27 classes per week

Step-by-step explanation:

Bo and Brica are yoga instructors

They teach 46 yoga classes each week
Brica teaches 11 fewer than twice as many as Bo

We need to find how many classes each instructor teaches per week

Assume that Bo teaches x classes per week

∵ Bo teaches x classes per week

∵ Brica teaches 11 fewer than twice as many as Bo

∵ Twice means times 2 and 11 fewer is - 11

- Multiply x by 2 and subtract 11 from the product

∴ Brica teaches 2x - 11 classes per week

∵ They teach 46 classes per week

- Add the number of their classes and equate the sum by 46

∴ x + 2x - 11 = 46

- Add the like terms in the left hand side

∴ 3x - 11 = 46

- Add 11 to both sides

∴ 3x = 57

- Divide both sides by 3

∴ x = 19

∵ Bo teaches x classes per week

∴ Bo teaches 19 classes per week

∵ Brica teaches 2x - 11 classes per week

∴ Brica teaches 2(19) - 11 = 27 classes per week

Bo teaches 19 classes and Brica teaches 27 classes per week

Learn more:

You can learn more about the linear equations in brainly.com/question/11306893

#LearnwithBrainly

5 0

3 years ago

anyone know how to do this?

Ugo [173]

Answer: A reasonable estimate of the minimum is 20.

8 0

2 years ago