Answer:
First Example: 3 1/2 + 4 3/4, Second Example: 6 3/8 + 7 9/15
Extra Example: 8 4/20 + 3 5/10
Step-by-step explanation:
First Example:
1/2 + 3/4
1/2 is equal to 2/4 so it is now compatible to be added to 3/4.
2/4 + 3/4
= 5/4
Now for the mixed numbers since its 3 and 4, 3 + 4 = 7.
Final answer is 7 5/4.
Second Example:
3/8 + 9/15
9/15 can be reduced to 3/5
Now the equation is 3/8 + 3/5
= 15/40 + 24/40 is an equivalent equation
15/40 + 24/40
= 39/40
Now for the mixed numbers since its 6 and 7, 6 + 7 = 13
Final answer is 13 39/40.
I am going to include one last example just in case you need one:
Third Example:
4/20 + 5/10
We can reduce these to
1/5 + 1/2
= 2/10 + 5/10 is the equivalent equation
2/10 + 5/10
= 7/10
Now for the mixed numbers since its 8 and 3, 8 + 3 = 11.
Final answer is 11 7/10.
I Hope this helps!
Answer:
51 deg
Step-by-step explanation:
Sin W=0.7771
(use calculator)
W = 50.996 deg
= 51 deg (to nearest degree)
Answer:
The method regarding the sampling to pick 200 sales representative is to make 20 groups of 10.
What is sampling?
Sampling simply means a process that's used in statistics where a predetermined number of observations are selected from the larger population.
In this case, the best way for the sales director to include 200 sales representatives, with an equal number from each region is simply to make 20 groups of 10.
Step-by-step explanation: correct on plato:)
Answer:
Step-by-step explanation:
<u>21. 1st scenario</u>
- B = fy + wz
- 100,000 = 15,000*4 + 500w
- 500w = 100,000 - 60,000
- 500w = 40,000
- w = 40,000/500
- w = 80
80 tons of wheat
<u>22. 2nd scenario</u>
- B = fy + wz
- 50,000 = 2y + 200*50
- 50,000 = 2y + 10,000
- 2y = 50,000 - 10,000
- 2y = 40,000
- y = 20,000
Fighter plane's price is $20,000
Answer:
The probability of using one or the other is 36%
Step-by-step explanation:
For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:
Probability of passing Professor Jones math class = 64% =0,64
P(J) = 0.64
Probabiliry of passing Professor Smith's physics class = 32% =0.32
P(S) = 0.32
Probability of passing both is = 30% = 0.30
P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram
We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:
P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%
If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.