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Mariulka [41]
3 years ago
10

Find the following quotients, and write the quotient in standard form. (a)- x^2-9 ÷ x-3 (b)- x^3-27 ÷ x-3 (c) x^4- 81 ÷ x-3

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

(a) x+3

(b) x^2+3x+9

(c) (x+3)(x^2+9)

Step-by-step explanation:

We have given that

(a) \frac{x^2-9}{x-3}

From the algebraic identity we know that

a^2-b^2=(a+b)(a-b)

So \frac{x^2-9}{x-3}=\frac{(x+3)(x-3)}{x-3}=x+3

(b) \frac{x^3-27}{x-3}

We know the algebraic identity

a^3-b^3=(a-b)(a^2+ab+b^2)

So \frac{x^3-27}{x-3}=\frac{x^3-3^3}{x-3}=\frac{(x-3)(x^2+3x+9)}{x-3}=x^2+3x+9

(c) We have given \frac{x^4-81}{x-3}

We know the algebraic identity

a^2-b^2=(a+b)(a-b)

\frac{x^4-81}{x-3}=\frac{(x^2)^2-(3^2)^2}{x-3}=\frac{(x^2-9)(x^2+9)}{x-3}=\frac{(x+3)(x-3)(x^2+9)}{x-3}=(x+3)(x^2+9)

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