Answer:
-6x(-7)( negative and negative = positive)
Step-by-step explanation:
-6x4= -24
-6x(-7) = 42
-3x8= -24
6x(-4) = -24
Answer:The value of the bulldozer after 3 years is $121950
Step-by-step explanation:
We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as
Annual depreciation expense =
(Cost of the asset - salvage value)/useful life of the asset.
From the given information,
Useful life = 23 years
Salvage value of the bulldozer = $14950
Cost of the new bulldozer is $138000
Therefore
Annual depreciation = (138000 - 14950)/ 23 = $5350
The value of the bulldozer at any point would be V. Therefore
5350 = (138000 - V)/ t
5350t = 138000 - V
V = 138000 - 5350t
The value of the bulldozer after 3 years would be
V = 138000 - 5350×3 = $121950
26x3=78
78-x=72
x=6
She needs to buy at least 6 more to have enough for 26 students
Using the monthly payments formula, it is found that a car with a value of at most $25,293.
<h3>What is the monthly payment formula?</h3>
It is given by:
In which:
- n is the number of payments.
In this problem, we have that the parameters are given as follows:
A = 400, n = 70, r = 0.035.
Hence:
r/12 = 0.035/12 = 0.002917.
Then we have to solve for P to find the maximum value of the car.
![P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B400%5B%281.002917%29%5E%7B70%7D-1%5D%7D%7B0.002917%281.002917%29%5E%7B70%7D%7D)
P = $25,293.
More can be learned about the monthly payments formula at brainly.com/question/26267630
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Answer:
<em>58,219 < 58,231</em>
Step-by-step explanation:
58,219 is less than 58,231, so the sentence is
58,219 < 58,231
